A compound possessing optical isomerism provided it has the molecular formula C₇H₁₆, would be:

1.	2,3-Dimethyl pentane	2.	2,2-Dimethyl butane
3.	2-Methyl hexane	4.	None of the above

 An alkene ‘A’ on ozonolysis gives a mixture of ethanal and pentan-3-one.
The IUPAC name of ‘A’ is :

1. 3-Ethylpent-2-ene

2. 3-Ethylpent-2- yne

3. 2-Ethylpent-3-ene

4. 3-Ethylpent-4-yne

The dihedral angle of the least stable conformer of ethane is:

Arrange the following carbanions in order of their decreasing stability:

A. \(\mathrm{H}_3 \mathrm{C}-\mathrm{C} \equiv \mathrm{C}^{-}\)
B. \(\mathrm{H}-\mathrm{C} \equiv \mathrm{C}^{-}\)
C. \(\mathrm{H}_3 \mathrm{C}-\mathrm{\bar{C}H_2}\)

1. A>B>C

2. B>A>C

3. C>B>A

4. C>A>B

The correct order of decreasing reactivity of the following compounds:

Chlorobenzene, 2,4-Dinitrochlorobenzene, and p-Nitrochlorobenzene

with an electrophile (E⁺)  is :

Out of the above alkenes, the ones that can give 2-methyl butane on hydrogenation are-

$\mathrm{Ethyne} \stackrel{?}{\to }$ $\mathrm{Benzene}$ 

The reagent used in the above conversion is:

1. Cr₂O₃

2. Alc. KOH

3. Red hot Fe

4. NaNH₂/liq.NH₃

Decreasing order of acidic behavior of benzene, n-hexane, and ethyne is -

1. Hexane > Ethyne > Benzene

2. Benzene > Hexane > Ethyne

3. Ethyne > Benzene > Hexane

4. Benzene > Ethyne > Hexene

Among the two isomers given above, the reason behind higher boiling point of one isomer as compared to the order is :

1. Cis - less polar than trans

2. Trans - more polar than cis

3. Cis - more intermolecular forces

4. Trans - more dipole-dipole interactions

The products formed after ozonolysis of Pent-2-ene are -

1. Ethanal, Methanal

2. Ethanal, Propanal

3. Ethanal, Butanal

4. Ethanal, Ethanal