Hydrolysis of sucrose is given by the following reaction
Sucrose + H2O Glucose + Fructose
If the equilibrium constant (Kc) is 21013 at 300 K, the value of at the same temperature will be:
1. 8.314 J mol-1 K-1300 Kln (21013)
2. 8.314 J mol-1 K-1300 Kln (31013)
3. -8.314 J mol-1 K-1300 Kln (41013)
4. -8.314 J mol-1 K-1300 Kln (21013)
A process among the following shows decrease in entropy is :
1. )
2. Evaporation of water
3. Expansion of a gas at a constant temperature
4. Sublimation of solid to gas
For a given reaction, ∆H = 35.5 kJ mol-1 and ∆S = 83.6 J K-1 mol-1 . The reaction is spontaneous at:
(Assume that ∆H and ∆S do not vary with temperature)
1. T > 425K
2. All temperatures
3. T > 298K
4. T<425K
The correct statement for a reversible process in a state of equilibrium is:
1. G = - 2.30RT log K
2. G = 2.30RT log K
3. Go = - 2.30RT log K
4. Go = 2.30RT log K
Given the reaction:
X2O4(l) → 2XO2(g)
ΔU = 2.1 kcal, ΔS = 20 cal K–1 at 300 K
The value of ΔG is:
1. 2.7 kcal
2. -2.7 kcal
3. 9.3 kcal
4. -9.3 kcal
In which of the following reactions, the standard reaction entropy change
is positive, and standard Gibb's energy change
decreases sharply with increasing temperature?
1. | C(graphite) + \(\frac{1}{2}\)O2(g) → CO(g) |
2. | CO(g) + \(\frac{1}{2}\)O2(g) → CO2(g) |
3. | Mg(s) + \(\frac{1}{2}\)O2(g) → MgO(s) |
4. | \(\frac{1}{2}\)C(graphite) + \(\frac{1}{2}\)O2(g) → \(\frac{1}{2}\)CO2(g) |
Standard entropies of X2, Y2 and XY3 are 60, 40 and 50JK-1mol-1 respectively. For the reaction
to be at equilibrium, the temperature should be:
1. 750 K
2. 1000 K
3. 1250 K
4. 500 K
For vaporization of water at 1 atmospheric pressure, the values of ∆H and ∆S are 40.63 kJ mol–1 and 108.8 JK–1 mol–1, respectively. The temperature when Gibbs energy change (∆G) for this transformation will be zero, is:
1. 393.4 K
2. 373.4 K
3. 293.4 K
4. 273.4 K