Column I (Process) |
Column II (Expression) |
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a. | No heat is absorbed by the system from the surroundings, but work (w) is done on the system. | i. | ∆U = q – w, closed system. |
b. | No work is done on the system, but q amount of heat is taken out from the system and given to the surroundings. | ii. | ∆U = wad, a wall is adiabatic. |
c. | w amount of work is done by the system and q amount of heat is supplied to the system. | iii. | ∆U = –q, thermally conducting walls. |
1. | a = i; b = ii; c = iii | 2. | a = ii; b = i; c = iii |
3. | a = ii; b = iii; c = i | 4. | a = iii; b = ii; c = i |
Two litres of an ideal gas at a pressure of 10 atm expands isothermally at 25 °C into a vacuum until its total volume is 10 litres. The amount of heat absorbed during expansion is:
1. 80 J
2. -80 J
3. Zero
4. 50 J
Two litres of an ideal gas at a pressure of 10 atm expands isothermally at 25 °C against a constant external pressure of 1 atm until its total volume is 10 litres. The amount of heat absorbed during expansion is-
1. 80 atm L
2. -80 atm L
3. -8 atm L
4. 8 atm L
.
Two litres of 1 mol an ideal gas at a pressure of 10 atm expands isothermally at 25 °C into a vacuum until its total volume is 10 litres. The amount of heat absorbed during expansion is:
(Given: The same expansion, for 1 mol of an ideal gas conducted reversibly.
log 5 = 0.699)
1. 51. 39 atm L
2. 39.36 atm L
3. 37. 34 atm ml
4. 26. 49 atm L
If water vapour is assumed to be a perfect gas, molar enthalpy change for vapourisation of 1 mol of water at 1 bar and 100°C is 41kJ mol–1. The internal energy change, when 1 mol of water is vapourised at 1 bar pressure and 100°C is:
1. 35.5 kJ mol–1
2. 37.9 kJ mol–1
3. 41 kJ mol–1
4. 44.2 kJ mol–1
1g of graphite is burnt in a bomb calorimeter in excess of oxygen at 298 K and 1 atmospheric pressure according to the equation
C (graphite) + O2(g) → CO2(g)
During the reaction, the temperature rises from 298 K to 299 K. If the heat capacity of the bomb calorimeter is 20.7kJ/K, the enthalpy change for the above reaction at 298 K and 1 atm is-
1. | – 2.48 ×102 kJ mol–1 | 2. | – 3.45 ×102 kJ mol–1 |
3. | – 1.65 ×102 kJ mol–1 | 4. | – 1.88 ×102 kJ mol–1 |
A swimmer coming out from a pool is covered with a film of water weighing about 18g. The internal energy of vaporization at 298K. is-
∆vap H⊖ for water at 298K= 44.01kJ mol–1
1. 38.63 kJ
2. 43.82 J
3. 41.53 kJ
4. 40.33 J
Assuming the water vapour to be a perfect gas. When 1 mol of water at 100°C and 1 bar pressure is converted to ice at 0°C, the change in internal energy is-
(The enthalpy of fusion of ice = 6.00 kJ mol-1 , heat capacity of water = 4.2 J/g°C)
1. 13.56 kJ mol-1
2. -12.16 kJ mol-1
3. -13.56 kJ mol-1
4. 12.16 kJ mol-1
The combustion of one mole of benzene takes place at 298 K and 1 atm. After combustion, CO2(g) and H2O (l)
are produced and 3267.0 kJ of heat is liberated.
The standard enthalpy of formation, ∆fH⊖ of benzene is:
(Standard enthalpies of formation of CO2(g) and are –393.5 kJ mol–1 and – 285.83 kJ mol–1 respectively.)
1. 54. 24 kJ mol–1
2. 48. 51 kJ mol–1
3. 66. 11 kJ mol–1
4. 15. 21 kJ mol–1
(i) | When liquid crystallizes into a solid, entropy increases. |
(ii) | When the temperature of a crystalline solid is raised from 0 K to 115 K then entropy increases. |
(iii) | 2 NaHCO3 (s) →Na2CO3 (s) +CO2(g)+H2O(g); Entropy increases. |
(iv) | H2(g)→2H(g) ; Entropy decreases. |