| n | l | m | |
| (a). | 2 | 2 | 1 |
| (b). | 3 | 2 | -2 |
| (c). | 3 | 2 | -1 |
| (d). | 2 | 1 | -1 |
| Statement I: | |
| Statement II: |
| a. | \( \small{n=3, \ell=2, m=0, s=\frac{-1}{2} \,\& \ \,n=3, \ell=2, m=-1, s=\frac{+1}{2}}\) |
| b. | \(\small{n=2, \ell=1, m=1 , \ s=\frac{-1}{2}\, \&\, \ n=3, \ell=1, m=1 \mathrm{~s}=\frac{+1}{2}}\) |
| c. | \(\small{n=4, \ell=2, m=-1, s=\frac{1}{2}\, \&\, \ n=3, \ell=2, m=-1, s=\frac{1}{2}}\) |
| (i). | n (principal quantum number) can have values 1, 2, 3, 4, ....... |
| (ii). | The number of orbitals for a given value of l is (2l+1). |
| (iii). | The value of spin quantum numbers is always \(\pm\frac12\). |
| (iv). | For l=5, the total number of orbitals is 9. |
| 1. | 1 and 2 | 2. | 3 and 3 |
| 3. | 1 and 0 | 4. | 2 and 1 |
The threshold frequency of a metal is \(1.4 \times 10^{15}sec^{-1}\). Calculate the minimum energy required to eject a photoelectron from this metal.
[Given: Planck’s constant, \(h = 6.6 \times 10^{-34} J sec\)]