Q. No.Two cells of emfs \(1~\text{V}\) and \(2~\text{V}\) and internal resistance \(2~\Omega\) and \(1~\Omega,\) respectively connected in parallel, gave a current of \(1~\text{A}\) through an external resistance. If the polarity of one cell is reversed, then value of current through the external resistance will be \(\dfrac{\alpha}{5} ~\text{A} .\) The value of \(\alpha\) is:
1. \(4\)
2. \(3\)
3. \(2\)
4. \(1\)
1. \(4\)
2. \(3\)
3. \(2\)
4. \(1\)
Subtopic: Â Grouping of Cells |
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Level 2: 60%+
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When an external resistance of \(5~\Omega\) \(5~\Omega\) \(2~\Omega\)
1. \(4\)
2. \(2\)
3. \(1\)
4. \(3\)
1. \(4\)
2. \(2\)
3. \(1\)
4. \(3\)
Subtopic: Â Grouping of Cells |
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For the two cells having same EMF \(E\) and internal resistance \(r,\) the current passing through the external resistor \(6 ~\Omega\) is same when both the cells are connected either in parallel or in series. The value of internal resistance \(r\) is: (in \(\Omega\))
1. \(3\)
2. \(4\)
3. \(9\)
4. \(6\)
1. \(3\)
2. \(4\)
3. \(9\)
4. \(6\)
Subtopic: Â Grouping of Cells |
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Two cells of emfs \(1 ~\text{V}\) and \(2 ~\text{V}\) and internal resistances \(2 ~\Omega\) and \(1 ~\Omega.\) respectively, are connected in series with an external resistance of \(6 ~\Omega.\) The total current in the circuit is \(I_1. \) Now the same two cells in parallel configuration are connected to same external resistance. In this case, the total current drawn is \(I_2.\) The value of \((I_1/I_2) \) is \(x/3.\) The value of \(x \) is:
1. \(35\)
2. \(8\)
3. \(4\)
4. \(2\)
1. \(35\)
2. \(8\)
3. \(4\)
4. \(2\)
Subtopic: Â Grouping of Cells |
Level 4: Below 35%
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Given below are two statements:
In the light of the above statements, choose the correct answer from the options given below
| Statements-I: | The equivalent emf of two non-ideal batteries connected in parallel is smaller than either of the two emfs. |
| Statements-II: | The equivalent internal resistance of two non-ideal batteries connected in parallel is smaller than the internal resistance of either of the two batteries. |
| 1. | Both Statement-I and Statement-II are true |
| 2. | Both Statement-I and Statement-II are false |
| 3. | Statement-I is true but statement-II is false |
| 4. | Statement-I is false but statement-II is true |
Subtopic: Â Grouping of Cells |
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Two cells one of emf \(8~\text V,\) internal resistance \(2~\Omega\) and the other of emf \(2 ~\text V\) and internal resistance \(4~\Omega\) are connected as shown in the figure.
Then the potential difference (in \(\text V\)) across the point \(AC\) is:
1. \(5\)
2. \(2\)
3. \(0\)
4. \(4\)
Then the potential difference (in \(\text V\)) across the point \(AC\) is:
1. \(5\)
2. \(2\)
3. \(0\)
4. \(4\)
Subtopic: Â Grouping of Cells |
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Eight identical batteries, each with an electromotive force (EMF) of \(5~\text{V}\) and internal resistance of \(1~\Omega,\) are connected in a circuit as shown in the diagram. An ideal voltmeter is connected across a portion of the circuit. What is the reading displayed by the ideal voltmeter?
1. \(5~\text V\)
2. \(2~\text V\)
3. \(7~\text V\)
4. zero
Subtopic: Â Grouping of Cells |
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Level 3: 35%-60%
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The current through a \(5~\Omega\) resistance remains the same, irrespective of its connection across a series or parallel combination of two identical cells. The internal resistance of the cell is:
| 1. | \(5~\Omega\) | 2. | \(10~\Omega\) |
| 3. | \(15~\Omega\) | 4. | \(20~\Omega\) |
Subtopic: Â Grouping of Cells |
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In the circuit shown in the figure, the internal resistances of \(5\) V and \(8\) V cells are \(3\) \(\Omega\) and 4 \(\Omega,\) respectively. The current (in amperes) flows through the 4 \(\Omega\) external resistor connected across points \(A\) and \(B\) is \(\dfrac{1}{n}~\text{A}.\)
The value of \(n =\)
1. \(5\)
2. \(15\)
3. \(10\)
4. \(7\)
The value of \(n =\)1. \(5\)
2. \(15\)
3. \(10\)
4. \(7\)
Subtopic: Â Grouping of Cells |
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Level 3: 35%-60%
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Two cells of the same emf but different internal resistances \(r_1\) and \(r_2\) are connected in series with a resistance \(R\). The value of resistance \(R\), for which the potential difference across the second cell is zero, is:
1. \(r_2-r_1\)
2. \(r_1-r_2\)
3. \(r_1\)
4. \(r_2\)
1. \(r_2-r_1\)
2. \(r_1-r_2\)
3. \(r_1\)
4. \(r_2\)
Subtopic: Â Grouping of Cells |
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Level 2: 60%+
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