The relative order of stability of the following species: \(\mathrm{O}_2,\mathrm{O}^+_2,\mathrm{O}^-_2~\mathrm{and}~\mathrm{O}^{2-}_2\) is -
| 1. | \(\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{O}^-_2>\mathrm{O}^{2-}_2\) | 2. | \(\mathrm{O}^{2-}_2>\mathrm{O}_2>\mathrm{O}^-_2>\mathrm{O}^{+}_2\) |
| 3. | \(\mathrm{O}_2>\mathrm{O}^+_2>\mathrm{O}^-_2>\mathrm{O}^{2-}_2\) | 4. | \(\mathrm{O}_2>\mathrm{O}^{2-}_2>\mathrm{O}^-_2>\mathrm{O}^{+}_2\) |
The positive and negative sign of the orbitals mean:
1. Wave function.
2. Probability density.
3. Quantum number of orbitals.
4. Frequency of orbitals.
In the option are given sequences of increasing bond order for the following species. The correct option is :
\(\mathrm{O}_2,\mathrm{N}_2,\mathrm{O}^+_2 ~\mathrm{and}~\mathrm{O}^-_2\)
| 1. | \(\mathrm{O}_2>\mathrm{N}_2>\mathrm{O}^+_2>\mathrm{O}^-_2\) | 2. | \(\mathrm{O}^-_2>\mathrm{O}_2>\mathrm{O}^+_2>\mathrm{N}_2\) |
| 3. | \(\mathrm{N}_2>\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{O}^-_2\) | 4. | \(\mathrm{O}^-_2>\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{N}_2\) |
Which of the following Molecular Orbital Theory explanations best accounts for the instability of the Be2 molecule?
1. The bond order of Be2 is one.
2. The bond order of Be2 is negative.
3. The bond order of Be2 is zero.
4. The bond order of Be2 is two.
The condition(s) required for the linear combination of atomic orbital is :
| 1. | Combining atomic orbitals must have the same or nearly the same energy. |
| 2. | Combining atomic orbitals must have proper orientations to ensure that the overlap is maximum. |
| 3. | Both 1 and 2 |
| 4. | None of the above |