A magnetic needle suspended parallel to a magnetic field requires \(\sqrt{3}~\text{J}\) of work to turn it through \(60^\circ\)
1. \(3\) N-m
2. \(\sqrt{3} \) N-m
3. \(\frac32\) N-m
4. \(2\sqrt{3}\) N-m
| Assertion (A): | Gauss's law for magnetism states that the net magnetic flux through any closed surface is zero. |
| Reason (R): | The magnetic monopoles do not exist. North and South poles occur in pairs, allowing vanishing net magnetic flux through the surface. |
| 1. | (A) is True but (R) is False. |
| 2. | (A) is False but (R) is True. |
| 3. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 4. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
A short bar magnet of magnetic moment \(0.4~\text {J/T}\) is placed in a uniform magnetic field of \(0.16~\text T.\) The magnet is in stable equilibrium when the potential energy is:
1. \(0.064~\text J\)
2. zero
3. \(-0.082~\text J\)
4. \(-0.064~\text J\)
| 1. | \(\dfrac{-mB}{2}\) | 2. | zero |
| 3. | \(-mB\) | 4. | \(mB\) |
A closely wound solenoid of \(2000\) turns and area of cross-section \(1.5\times10^{-4}\) m2 carries a current of \(2.0\) A. It is suspended through its center and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field \(5\times 10^{-2}\) tesla making an angle of \(30^{\circ}\) with the axis of the solenoid. The torque on the solenoid will be:
1. \(3\times 10^{-3}\) Nm
2. \(1.5\times 10^{-3}\) Nm
3. \(1.5\times 10^{-2}\) Nm
4. \(3\times 10^{-2}\) Nm
A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in the equilibrium state. The energy required to rotate it by \(60^{\circ}\) is \(W\). Now the torque required to keep the magnet in this new position is:
| 1. | \(\dfrac{W}{\sqrt{3}}\) | 2. | \(\sqrt{3}W\) |
| 3. | \(\dfrac{\sqrt{3}W}{2}\) | 4. | \(\dfrac{2W}{\sqrt{3}}\) |
A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in the equilibrium state. The energy required to rotate it by \(60^{\circ}\) is \(W\). Now the torque required to keep the magnet in this new position is:
1. \(\frac{W}{\sqrt{3}}\)
2. \(\sqrt{3} W\)
3. \(\frac{\sqrt{3} W}{2}\)
4. \(\frac{2 W}{\sqrt{3}}\)
| 1. | negative | 2. | zero |
| 3. | positive | 4. | infinity |
The magnetic field at the centre of a circular loop of area \(A\) is \(B.\) The magnetic moment of the loop is:
| 1. | \(\dfrac{BA^2}{\mu_0\pi}\) | 2. | \(\dfrac{BA\sqrt A}{\mu_0}\) |
| 3. | \(\dfrac{BA\sqrt A}{\mu_0\pi}\) | 4. | \(\dfrac{2BA\sqrt A}{\mu_0\sqrt\pi}\) |
A current-carrying loop placed in a magnetic field behaves like a:
1. magnetic dipole
2. magnetic substance
3. magnetic pole
4. all are true