If the potential difference across ends of a metallic wire is doubled, the drift velocity of charge carriers will become:
1. double
2. half
3. four times
4. one-fourth
1. | 28 C | 2. | 30.5 C |
3. | 8 C | 4. | 82 C |
The current in a wire varies with time according to the equation I=(4+2t), where I is in ampere and t is in seconds. The quantity of charge which has passed through a cross-section of the wire during the time t=2 s to t=6 s will be:
1. | 60 C | 2. | 24 C |
3. | 48 C | 4. | 30 C |
A charged particle having drift velocity of 7.5×10−4 ms−1 in an electric field of 3×10−10 Vm−1, has mobility of:
1. 2.5×106 m2V−1s−1
2. 2.5×10−6 m2V−1s−1
3. 2.25×10−15 m2V−1s−1
4. 2.25×1015 m2V−1s−1
Drift velocity vd varies with the intensity of the electric field as per the relation:
1. vd∝E
2. vd∝1E
3. vd=constant
4. vd∝E2
The drift velocity of free electrons in a conductor is v when a current i is flowing in it. If both the radius and current are doubled, then the drift velocity will be:
1. | v | 2. | v2 |
3. | v4 | 4. | v8 |
1. | not change |
2. | be halved |
3. | be four times |
4. | be doubled |
1. | current density | 2. | current |
3. | drift velocity | 4. | electric field |
A current passes through a wire of variable cross-section in steady-state as shown. Then incorrect statement is:
1. | Current density increases in the direction of the current. |
2. | Potential increases in the direction of the current. |
3. | Electric field increases in the direction of the current. |
4. | Drift speed increases in the direction of the current. |