- 1(current)
Q. No.An ideal gas forms the working substance of a Carnot engine, and is taken around the Carnot cycle. We form the integral: \(I=\int\dfrac{dQ}{T},\)
where \(dQ\) is the heat supplied to the gas and \(T\) is the temperature of the gas. The integral is evaluated over the entire cycle. The value of the integral \(I\) is:
where \(dQ\) is the heat supplied to the gas and \(T\) is the temperature of the gas. The integral is evaluated over the entire cycle. The value of the integral \(I\) is:
| 1. | zero |
| 2. | negative |
| 3. | positive |
| 4. | non-negative(positive or zero) |
Subtopic: Â Carnot Engine |
 50%
Level 3: 35%-60%
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Two Carnot engines \(\mathrm{(I,II)}\) are working in tandem so that the heat rejected by the first one equals that absorbed by the second one in each cycle; the heat being rejected at a rate of \(9~\text W\) by engine \(\mathrm I.\) The work output of engine \(\mathrm I\) is \(1~\text W,\) while that of engine \(\mathrm{II}\) is \(3~\text W.\) The overall efficiency is:
| 1. | \(40\%\) | 2. | \(43\%\) |
| 3. | \(22.5\%\) | 4. | \(20\%\) |
Subtopic: Â Carnot Engine |
Level 3: 35%-60%
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Q. No.
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