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One of the satellites of Jupiter has an orbital period of \(1.769\) days and the radius of the orbit is \(4.22 \times 10^{8}\) m. The ratio of the mass of Jupiter and the mass of the sun nearly is: (Mass of the sun \(\approx 2\times 10^{30}~\text{kg}\))
1. \(1000:1\)
2. \(1:1000\)
3. \(1:1\)
4. \(2000:3\)
Subtopic: Newton's Law of Gravitation |
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If the mean orbital radius of the Earth around the sun is \(1.5 \times 10^8 ~\text{km}.\) Then the mass of the Sun is approximately:
1. \(3 × {10}^{34}~\text{kg}\)
2. \(2 × 10^{30}~\text{kg}\)
3. \(1.5 × {10}^{28}~\text{kg}\)
4. \(1 × {10}^{35}~\text{kg}\)
1. \(3 × {10}^{34}~\text{kg}\)
2. \(2 × 10^{30}~\text{kg}\)
3. \(1.5 × {10}^{28}~\text{kg}\)
4. \(1 × {10}^{35}~\text{kg}\)
Subtopic: Newton's Law of Gravitation |
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