An LED is constructed from \(\mathrm{Ga\text-As\text-P}\) semiconducting material with an energy gap of \(1.9~\text{eV}.\) What is the wavelength of the emitted light and what colour does it correspond to?
(take \(h=6.63\times10^{-34}~\text{J-s}\) and \(c=3\times10^8~\text{m/s}\))

1. \(1046~\text{nm}\) and red colour
2. \(654~\text{nm}\) and orange colour
3. \(1046~\text{nm}\) and blue colour
4. \(654~\text{nm}\) and red colour
Subtopic:  Energy Band theory |
Level 3: 35%-60%
JEE
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The energy band gap of semiconducting material to produce violet (wavelength \(=4000~\mathring{A}\)) LED is (nearly):
1. \(3~\text{eV}\)
2. \(5~\text{eV}\)
3. \(1~\text{eV}\)
4. \(7~\text{eV}\)
Subtopic:  Energy Band theory |
 88%
Level 1: 80%+
JEE
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The acceptor level of a p-type semiconductor is \(6\) eV. The maximum wavelength of light which can create a hole would be : Given \(h c=1242\) eV-nm.
1. \(407\) nm
2. \(207\) nm
3. \(103.5\) nm
4. \(414\) nm
Subtopic:  Energy Band theory |
 90%
Level 1: 80%+
JEE
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