In the given circuit diagram, the total charge stored in capacitors is \(50~\mu \text{C}.\) The value of capacitor \(x \) is: 

1. \(3\)
2. \(0\)
3. \(2\)
4. \(1\)
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A parallel plate capacitor with air as a medium between the plates has a capacitance of \(10~\mu \text{F}.\) The area of the capacitor is divided into two equal halves and filled with two media having dielectric constants \(k_1=2\) and \(k_2=4.\) The capacitance of the new system will be:
1. \(10~\mu \text{F}\)
2. \(20~\mu \text{F}\)
3. \(30~\mu \text{F}\)
4. \(40~\mu \text{F}\)
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Initially, uncharged capacitors are connected in a circuit, as shown in the diagram. The potentials at \(C,\) \(D\) satisfy: \(V_C=V_D.\) Then:
1. \(C_1C_2 = C_3C_4\) 2. \(\dfrac{C_1}{C_4}=\dfrac{C_2}{C_3}\)
3. \(\dfrac{C_1}{C_3}=\dfrac{C_2}{C_4}\) 4. \(C_1C_3 = C_2C_4\)
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In the given circuit, what will be the charge on the \(12~\mu\text{F}\) capacitor?
1. \(144~\mu \text{C}\) 2. \(72~\mu \text{C}\)
3. \(36~\mu \text{C}\) 4. \(28~\mu \text{C}\)
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Two parallel-plate capacitors, each having air between their plates, have plate areas \(100~\text {cm}^2\) and \(500~\text {cm}^2,\) respectively. Both capacitors carry the same charge and are at the same potential. If the distance between the plates of the first capacitor is \(0.5 ~\text {mm},\) what is the distance between the plates of the second capacitor?

1. \(0.10 \text { cm}\) 2. \(0.15 \text { cm} \)
3. \(0.20 \text { cm}\) 4. \(0.25 \text { cm}\)
Subtopic:  Capacitance |
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A capacitor \(C_1\) of capacitance \(5~\mu\text{F}\) is charged to a potential of \(30~\text{V}\) using a battery. The battery is then removed and the charged capacitor is connected to an uncharged capacitor \(C_2\) of capacitance \(10~\mu\text{F}\) as shown in the figure. When the switch is closed charge flows between the capacitors. At equilibrium, the charge on the capacitors \(C_2\) is:
          
1. \(100~\mu\text{C}\)
2. \(50~\mu\text{C}\)
3. \(125~\mu\text{C}\)
4. \(75~\mu\text{C}\)
Subtopic:  Capacitance |
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Given below are two statements: 
Assertion (A): The plates of a parallel-plate capacitor attract each other when it is charged.
Reason (R): The plates carry opposite charges and hence they attract by Coulomb's law.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Capacitance |
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The distance between the two plates of a parallel plate capacitor is doubled, and the area of each plate is halved. If \(C\) is its initial capacitance, its final capacitance is equal to:
1. \(2C\) 2. \(\dfrac{C}{2}\)
3. \(4C\) 4. \(\dfrac{C}{4}\)
Subtopic:  Capacitance |
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NEET - 2022
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In the given circuit, the charge on \(4~\mu \text{F}\) capacitor will be:

                     
1. \(5.4~\mu \text{C}\)
2. \(9.6~\mu \text{C}\)
3. \(13.4~\mu \text{C}\)
4. \(24~\mu \text{C}\)

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Consider a parallel plate capacitor of plate area '\(A\)', plate separation '\(d\)'. Suppose that the plates are given charges \(+Q,-Q\) respectively. The force between the two plates is proportional to:
1. \(\dfrac{Q^2}{d^2}\) 2. \(\dfrac{Q^2}{A}\)
3. \(\dfrac{Q^2}{d\sqrt A}\) 4. \(\dfrac{Q^2\sqrt A}{d^3}\)
Subtopic:  Capacitance |
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