Focal lengths of objective and eyepiece of a compound microscope are 2 cm and 6.25 cm respectively. An object AB is placed at a distance of 2.5 cm from the objective which forms the image A'B' as shown in the figure. Maximum magnifying power in this case, will be:
       

1. 10 2. 20
3. 5 4. 25
Subtopic:  Simple & Compound Microscope |
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The correct statement is:

1. The intermediate image in a compound microscope is real, erect and magnified
2. Intermediate image in a compound microscope is real, inverted, but diminished
3. Intermediate image in a compound microscope is virtual, erect and magnified
4. Intermediate image in a compound microscope is real, inverted and magnified
Subtopic:  Simple & Compound Microscope |
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In the case of a compound microscope, the image formed by the objective lens is:

1. Virtual, erect, and diminished.
2. Real, erect, and magnified.
3. Virtual, inverted, and enlarged. 
4. Real, inverted, and enlarged.

Subtopic:  Simple & Compound Microscope |
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The magnification of a compound microscope for the final image at the least distance of distinct vision is \(90\). The magnification of the objective lens is \(15\). The value of the focal length of the eyepiece will be: 
1. \(5\) cm
2. \(6\) cm
3. \(1\over6\) cm
4. \(12\) cm

Subtopic:  Simple & Compound Microscope |
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If the focal length of the objective lens is increased, then magnifying power of:

1. microscope will increase but that of telescope decrease
2. microscope and telescope both will increase
3. microscope and telescope both will decrease
4. microscope will decrease but that of the telescope will increase
Subtopic:  Simple & Compound Microscope |
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AIPMT - 2014

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A microscope has an objective of focal length 1.5 cm and an eye–piece of focal length 2.5 cm. If the distance between objective and eye-piece is 25 cm, what is the approximate value of magnification produced for relaxed eye?

1. 75 2. 110
3. 140 4. 25
Subtopic:  Simple & Compound Microscope |
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The focal length of the objective lens and the eye lens is 4 mm and 25 mm respectively in a compound microscope. The distance between objective and eyepiece lens is 16 cm. Find its magnifying power for relaxed eye position:

1. 32.75   
2. 327.5 
3. 0.3275 
4. None of the above

Subtopic:  Simple & Compound Microscope |
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In a compound microscope, the magnification is \(95\), the distance of the object from the objective lens is \(\frac{1}{3.8}~\text{cm}\) and the focal length of the objective is \(\frac{1}{4}~\text{cm}\). What is the magnification of the eyepiece when the final image is formed at the least distance of distinct vision?
1. \(5\)
2. \(10\)
3. \(100\)
4. none of the above

Subtopic:  Simple & Compound Microscope |
From NCERT
AIPMT - 1999

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