- 1(current)
Q. No.| 1. | \(Z\) protons and \(A-Z\) neutrons |
| 2. | \(Z\) protons and \(A\) neutrons |
| 3. | \(A\) protons and \(Z-A\) neutrons |
| 4. | \(Z\) neutrons and \(A-Z\) protons |
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| 1. | \({}_{34}^{74}\mathrm{Se}, {}_{31}^{71}\mathrm{Ca}\) | 2. | \({}_{42}^{92}\mathrm{Mo}, {}_{40}^{92}\mathrm{Zr}\) |
| 3. | \({}_{38}^{81}\mathrm{Sr}, {}_{38}^{86}\mathrm{Sr}\) | 4. | \({}_{20}^{40}\mathrm{Ca}, {}_{16}^{32}\mathrm{S}\) |
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| 1. | \(25.8\) MeV | 2. | \(23.6\) MeV |
| 3. | \(19.2\) MeV | 4. | \(30.2\) MeV |
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1. \(E_a-3E_b= Q\)
2. \(3E_b-E_a= Q\)
3. \(E_a+ 3E_b=Q\)
4. \(E_b+ 3E_a=Q\)
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| 1. | \(M(A, Z)=ZM_p+(A-Z) M_n-B E / c^2\) |
| 2. | \({M}({A}, {Z})={ZM}_{p}+({A}-{Z}) {M}_{n}+{BE}\) |
| 3. | \(M(A, Z)=ZM_p+(A-Z) M_n-B E\) |
| 4. | \({M}({A}, {Z})={ZM}_{p}+({A}-{Z}) {M}_{n}+{BE/c}^2 \) |
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1. \(19.2\) MeV
2. \(23.6\) MeV
3. \(26.9\) MeV
4. \(13.9\) MeV
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if the binding energies of \({}_{1}^{2}\mathrm{H}, {}_{1}^{3}\mathrm{H},\) and \({}_{2}^{4}\mathrm{He}\) are respectively \(a,b,\) and \(c\) (in MeV), then the energy in (MeV) released in this reaction is:
1. \(c+a-b\)
2. \(c-a-b\)
3. \(a+b+c\)
4. \(a+b-c\)
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The mass of a \({}_{3}^{7}\mathrm{Li}\) nucleus is \(0.042\) u less than the sum of the masses of all its nucleons. The binding energy per nucleon of the \({}_{3}^{7}\mathrm{Li}\) nucleus is near:
1. \(4.6\) MeV
2. \(5.6\) MeV
3. \(3.9\) MeV
4. \(23\) MeV
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The Binding energy per nucleon of \(^{7}_{3}\mathrm{Li}\) and \(^{4}_{2}\mathrm{He}\) nucleon are \(5.60~\text{MeV}\) and \(7.06~\text{MeV}\), respectively. In the nuclear reaction \(^{7}_{3}\mathrm{Li} + ^{1}_{1}\mathrm{H} \rightarrow ^{4}_{2}\mathrm{He} + ^{4}_{2}\mathrm{He} +Q\), the value of energy \(Q\) released is:
1. \(19.6~\text{MeV}\)
2. \(-2.4~\text{MeV}\)
3. \(8.4~\text{MeV}\)
4. \(17.3~\text{MeV}\)
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- 1(current)
Q. No.
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