A solution containing 10 g/dm3 of urea (molecular mass = 60 g mol-1) is isotonic with a 5 % solution of a non-volatile solute. The molecular mass of this non-volatile solute is:

1. 25 g mol-1 2. 300 g mol-1
3. 350 g mol-1 4. 200 g mol-1
Subtopic:  Introduction & Colligative properties |
 82%
From NCERT
AIPMT - 2006

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


For an ideal solution, the non-zero value will be for:

1. \(\Delta H_\text{mix}\)
2. \(\Delta S_\text{mix}\)
3. \(\Delta V_\text{mix}\)
4. \(\Delta P=P_{\text{observed}}-P_{\text{Raoult}}\)
Subtopic:  Introduction & Colligative properties |
 84%
From NCERT
NEET - 2015

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


The correct match for the below table is:
Type of solution  Example
a. Solid in gas i. Aerated water
b. Gas in liquid  ii. Smoke
c. Liquid in solid iii. Solution of hydrogen in palladium 
d. Gas in solid iv. Amalgams
   
a b c d
1. i iii iv ii
2. ii i iv iii
3. iii i iv ii
4. iv i ii iii
Subtopic:  Introduction & Colligative properties |
 77%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


advertisementadvertisement

Colligative properties are dependent on which of the following factors?

1. The nature of the solute particles dissolved in the solution.
2. The number of solute particles in the solution.
3. The physical properties of the solute particles dissolved in the solution.
4. The nature of solvent particles.

Subtopic:  Introduction & Colligative properties |
 79%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


The solubility of a gas in a liquid decreases with an increase in temperature because:

1. Dissolution of a gas in a liquid is an endothermic process. 
2. Dissolution of a gas in a liquid is an exothermic process. 
3. Gases are highly compressible.
4. All of the above.
Subtopic:  Introduction & Colligative properties |
 70%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


An aqueous solution of hydrochloric acid -

1. Obeys Raoult's law

2. Shows negative deviations from Raoult's law

3. Shows positive deviations from Raoult's law

4. Obeys Henry's law at all compositions

Subtopic:  Introduction & Colligative properties |
 70%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


advertisementadvertisement

Consider the following statements about the composition of the vapour over an ideal 1:1 molar mixture of benzene and toluene. The correct statement is:

Assume that the temperature is constant at 25 oC.
(Given, vapour pressure data at 25 °C, benzene = 12.8 kPa, toluene = 3.85 kPa)

1. The vapour will contain a higher percentage of toluene.
2. The vapour will contain equal amounts of benzene and toluene.
3. Not enough information is given to make a prediction.
4. The vapour will contain a higher percentage of benzene.
Subtopic:  Introduction & Colligative properties |
 63%
From NCERT
NEET - 2016

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


To minimize the painful effects accompanying deep sea diving, oxygen diluted with less soluble helium gas is used as breathing gas by the divers. This is an example of the application of:

1. Raoult's law 2. Henry's law
3. Ideal gas Equation 4. All of the above
Subtopic:  Concentration Terms & Henry's Law |
 84%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


The graph representing Henry's law is given below:

    

The value of the slope will be

1. \(4\times10^{-4}~\mathrm{torr}\) 2. \(5\times10^{-4}~\mathrm{torr}\)
3. \(4\times10^{4}~\mathrm{torr}\) 4. \(5\times10^{4}~\mathrm{torr}\)

Subtopic:  Concentration Terms & Henry's Law |
 81%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


advertisementadvertisement

Henry’s law constant for the solution of methane in benzene at 298 K is 4.27 × 105 mm Hg. The mole fraction of methane in benzene at 298 K under 760 mm Hg will be:

1. 1.85 × 105

2. 192 × 104

3. 178 × 105

4. 18.7 × 10–5

Subtopic:  Concentration Terms & Henry's Law |
 74%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.