The net resistance of the circuit between \(A\) and \(B\) is:
1. | \(\frac{8}{3}~\Omega\) | 2. | \(\frac{14}{3}~\Omega\) |
3. | \(\frac{16}{3}~\Omega\) | 4. | \(\frac{22}{3}~\Omega\) |
1. | \(7R\) | 2. | \(5R\) |
3. | \(4R\) | 4. | \(3R\) |
In the circuit shown in the figure below, the current supplied by the battery is:
1. \(2\) A
2. \(1\) A
3. \(0.5\) A
4. \(0.4\) A
In a Wheatstone bridge, all four arms have equal resistance \(R.\) If the resistance of the galvanometer arm is also \(R,\) the equivalent resistance of the combination is:
1. | \(R/4\) | 2. | \(R/2\) |
3. | \(R\) | 4. | \(2R\) |
In the circuit shown in the figure below, if the potential difference between \(B\) and \(D\) is zero, then value of the unknown resistance \(X\) is:
1. | \(4~\Omega\) | 2. | \(2~\Omega\) |
3. | \(3~\Omega\) | 4. | EMF of a cell is required to find the value of \(X\) |
Three resistances \(\mathrm P\), \(\mathrm Q\), and \(\mathrm R\), each of \(2~\Omega\) and an unknown resistance \(\mathrm{S}\) form the four arms of a Wheatstone bridge circuit. When the resistance of \(6~\Omega\) is connected in parallel to \(\mathrm{S}\), the bridge gets balanced. What is the value of \(\mathrm{S}\)?
1. | \(2~\Omega\) | 2. | \(3~\Omega\) |
3. | \(6~\Omega\) | 4. | \(1~\Omega\) |
For the network shown in the figure below, the value of the current \(i\) is:
1. \(\frac{18V}{5}\)
2. \(\frac{5V}{9}\)
3. \(\frac{9V}{35}\)
4. \(\frac{5V}{18}\)
In the Wheatstone's bridge (shown in the figure below) \(X=Y\) and \(A>B\). The direction of the current between \(a\) and \(b\) will be:
1. | from \(a\) to \(b\). |
2. | from \(b\) to \(a\). |
3. | from \(b\) to \(a\) through \(c\). |
4. | from \(a\) to \(b\) through \(c\). |
Five equal resistances each of resistance \(R\) are connected as shown in the figure below. A battery of \(V\) volts is connected between \(A\) and \(B\). The current flowing in \(AFCEB\) will be:
1. \(\frac{V}{R}\)
2. \(\frac{V}{2R}\)
3. \(\frac{2V}{R}\)
4. \(\frac{3V}{R}\)