The combination of gates shown below is equivalent to:
1. AND gate
2. XOR gate
3. NOR gate
4. NAND gate
Find the base resistance in the circuit below, if \(\beta_{DC} =90\) and \(V_{BE}=0.7~V.\)
1. 83
2. 41 k
3. 83 k
4. 41
The given circuit has two ideal diodes connected as shown in the figure below. The current flowing through the resistance \(R_1\) will be:

| 1. | \(2.5~\text A\) | 2. | \(10.0~\text A\) |
| 3. | \(1.43~\text A\) | 4. | \(3.13~\text A\) |
In the energy band diagram of a material shown below, the open circles and filled circles denote holes and electrons respectively. The material is a/an:

| 1. | \(\mathrm{p}\text-\)type semiconductor |
| 2. | insulator |
| 3. | metal |
| 4. | \(\mathrm{n}\text-\)type semiconductor |
| 1. | (i) < (ii) < (iii) | 2. | (iii) < (ii) < (i) |
| 3. | (ii) = (iii) < (i) | 4. | (i) = (iii) < (ii) |
| 1. | the drift of holes. |
| 2. | diffusion of charge carriers. |
| 3. | migration of impurity ions. |
| 4. | drift of electrons. |
The output in the circuit shown in the figure taken across a capacitor is:
| 1. | 2. | ||
| 3. | 4. |
Logic gates \(X\) and \(Y\) have the truth tables shown below:

| \(X\) | ||
| \(P\) | \(Q\) | \(R\) |
| \(0\) | \(0\) | \(0\) |
| \(1\) | \(0\) | \(0\) |
| \(0\) | \(1\) | \(0\) |
| \(1\) | \(1\) | \(1\) |
| \(Y\) | |
| \(P\) | \(R\) |
| \(0\) | \(1\) |
| \(1\) | \(0\) |
When the output of \(X\) is connected to the input of \(Y\), the resulting combination is equivalent to a single:
1. NOT gate
2. OR gate
3. NAND gate
4. AND gate
The LED:
| 1. | is reverse-biased. |
| 2. | is forward-biased. |
| 3. | can be made of \(\mathrm{GaAs}.\) |
| 4. | both (2) and (3) are correct. |
| 1. | \(0,0\) | 2. | \(5~\text{mA},5~\text{mA}\) |
| 3. | \(5~\text{mA},0\) | 4. | \(0,5~\text{mA}\) |