When acidified the solution is added to Sn++ salt then Sn++ changes to
1. Sn
2. Sn3+
3. Sn4+
4. Sn+
Highest oxidation state of manganese in fluoride is +4(Mn) but highest oxidation state in oxides is +7() because
1. | Fluorine is more electronegative than oxygen |
2. | Fluorine does not possess d orbitals |
3. | Fluorine stabilises lower oxidation state |
4. | In covalent compounds, fluorine can form single bond only while oxygen forms double bond |
Although zirconium belongs to 4d transition series and hafnium to 5d transition series even then they show similar physical and chemical properties because............. .
1. | Both belong to d-block |
2. | Both have same number of electrons |
3. | Both have similar atomic radius |
4. | Both belong to the same group of the Periodic Table |
Why is HCl not used to make the medium acidic in oxidation reactions of in acidic medium?
1. | Both HCl and KMnO4 act as oxidising agents |
2. | KMnO4 oxidises HCl into Cl2, which is also an oxidising agent |
3. | KMnO4 is a weaker oxidising agent than HCl |
4. | KMnO4 acts as a reducing agent in the presence of HCl |
Match Column I (Catalyst) with Column II (Process), and mark the appropriate option:
Column I - (Catalyst) | Column II - (Process) | ||
A. | Ni in the presence of hydrogen | 1. | Contact process |
B. | Cu2Cl2 | 2. | Vegetable oil to ghee |
C. | V2O5 | 3. | Sandmeyer reaction |
D. | Finely divided iron | 4. | Haber's process |
5. | Decomposition of KClO3 |
Codes:
A | B | C | D | |
1. | 3 | 4 | 2 | 5 |
2. | 2 | 3 | 1 | 4 |
3. | 5 | 4 | 3 | 2 |
4. | 4 | 5 | 3 | 2 |
Match the compounds/elements given in Column I with uses given in Column II.
Column (Compound/element) |
Column II (Use) |
||
A. | Lanthanoid oxide | 1. | Petroleum cracking |
B. | Lanthanoid | 2. | Television screen |
C. | Mischmetal | 3. | Lanthanoid metal + iron |
D. | Mixed oxides of lanthanoids are employed |
4. | Production of iron alloy |
Codes
Options: | A | B | C | D |
1. | 2 | 1 | 4 | 3 |
2. | 1 | 2 | 3 | 4 |
3. | 2 | 4 | 3 | 1 |
4. | 4 | 1 | 3 | 2 |
Match the properties given in Column I with uses given in Column II
Column I-(Property) | Column II-(Metal) | ||
A. | An element that can show +8 oxidation state | 1. | Mn |
B | 3d block element that can show up to +7 | 2. | Cr |
C | 3d block element with the highest melting point | 3. | Os |
4. | Fe |
A | B | C | |
1. | 3 | 1 | 2 |
2. | 1 | 2 | 3 |
3. | 1 | 4 | 3 |
4. | 4 | 2 | 3 |
Match the statements given in Column I with the oxidation states given in Column and mark the correct option.
Column I |
Column II |
A. Oxidation state of Mn in is |
1. +2 2. +3 |
B. Most stable oxidation state of Mn is |
3. +4 |
C. Most stable oxidation state of Mn in oxides is |
4. +5 |
D. Characteristic oxidation state of lanthanoids is |
5. +7 |
Codes
Options: | A | B | C | D |
1. | 2 | 3 | 4 | 1 |
2. | 3 | 1 | 5 | 2 |
3. | 5 | 4 | 3 | 2 |
4. | 4 | 5 | 3 | 2 |
Match the solutions given in Column I with the colours given in Column II.
Column I - (Aqueous solution of salt) | Column II - (Colour) |
A. FeSO4 .7H2O | 1. Green |
B. NiCl2 . 4H2O | 2. Light pink |
C. MnCl2.4H2O | 3. Blue |
D. CoCl2. 6H2O | 4. Pale green |
5. Pink |
Codes
A | B | C | D | |
1. | 2 | 3 | 4 | 1 |
2. | 1 | 2 | 3 | 5 |
3. | 5 | 4 | 3 | 2 |
4. | 4 | 1 | 2 | 5 |
Match the property given in Column I with the element given in Column II.
Column I ( Property) |
Column II (Element) |
A. Lanthanoid which shows + 4 oxidation state |
1. Pm |
B. Radioactive lanthanoid |
2. Ce |
C. Lanthanoid which has 4 electronic configurations in +3 oxidation state |
3. Lu |
D. Lanthanoid which has 4 electronic configurations in +3 oxidation state |
4. Gd |
Codes
Options: | A | B | C | D |
1. | 2 | 4 | 1 | 3 |
2. | 1 | 2 | 3 | 4 |
3. | 2 | 1 | 4 | 3 |
4. | 4 | 1 | 3 | 2 |