The equation of the trajectory of a projectile is given as \(y = 4x-\dfrac{1}{4x^2}.\) The range of the projectile is:
1. 1 m
2. 32 m
3. 16 m
4. 48 m
A projectile is fired from the surface of the earth with a velocity of \(5\text{ m/s}\) and at an angle \(\theta \) with the horizontal. Another projectile fired from another planet with a velocity of \(3\text{ m/s}\) at the same angle follows a trajectory that is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is: (given = \(9.8\text{ m/s}^2\))
1. \(3.5\)
2. \(5.9\)
3. \(16.3\)
4. \(110.8\)
| 1. | Their time of flight will be the same. |
| 2. | Their maximum height will be the same. |
| 3. | Their range will be the same. |
| 4. | Their landing velocity will be the same. |
The horizontal range is four times the maximum height attained by a projectile. The angle of projection is
1. \(90^{\circ}\)
2. \(60^{\circ}\)
3. \(45^{\circ}\)
4. \(30^{\circ}\)
Two bullets are fired horizontally with different velocities from the same height. Which will reach the ground first?
| 1. | slower one |
| 2. | faster one |
| 3. | both will reach simultaneously |
| 4. | cannot be predicted |
| 1. | \(25~\text{m/s} \) | 2. | \(40~\text{m/s}\) |
| 3. | \(31.25~\text{m/s}\) | 4. | \(12.5~\text{m/s}\) |
| Assertion (A): | When a body is projected at an angle of \(45^\circ,\) its range is maximum. |
| Reason (R): | For maximum range, the value of \(\text{sin}2 \theta\) should be equal to one. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |