An ammeter A of finite resistance and a resistor R are joined in series to an ideal cell C. A potentiometer P is joined in parallel to R. The ammeter reading is ${\mathrm{I}}_0$ and the potentiometer reading is V₀ . P is now replaced by a voltmeter of finite resistance. The ammeter reading now is I and the voltmeter reading is V.

It can be concluded that:

1. $\mathrm{I}>{\mathrm{I}}_0,$ $\mathrm{V}<{\mathrm{V}}_0$

2. $\mathrm{I}>{\mathrm{I}}_0,$ $\mathrm{V}={\mathrm{V}}_0$

3. $\mathrm{I}={\mathrm{I}}_0,$ $\mathrm{V}<{\mathrm{V}}_0$

4. $\mathrm{I}<{\mathrm{I}}_0,$ $\mathrm{V}={\mathrm{V}}_0$

In the following circuit, the battery \(E_1\) has an emf of \(12\) volts and zero internal resistance while the battery \(E\) has an emf of \(2\) volts. If the galvanometer \(G\) reads zero, then the value of the resistance \(X\) in ohms is:

The figure below shows currents in a part of the electric circuit. The current \(i\) is:

What is the equivalent resistance between \(A\) and \(B\) in the figure below if \(R= 3~\Omega?\)
                    
1. \(9~\Omega\)
2. \(12~\Omega\)
3. \(15~\Omega\)
4. None of these$$

The potentiometer wire AB is 600 cm long. At what distance from A should the jockey J touch the wire to get zero deflection in the galvanometer?

1. 320 cm

2. 120 cm

3. 20 cm

4. 450 cm

A torch bulb rated \(4.5\) W, \(1.5\) V is connected as shown in the figure below. The emf of the cell needed to make the bulb glow at full intensity is:

The metre bridge shown is in a balanced position with \(\frac{P}{Q} = \frac{l_1}{l_2}\). If we now interchange the position of the galvanometer and the cell, will the bridge work? If yes, what will be the balanced condition?

What is total resistance across terminals \(A\) and \(B\) in the following network?

The Wheatstone bridge shown in the figure below is balanced when the uniform slide wire \(AB\) is divided as shown. Value of the resistance \(X\) is:
          

1. \(3~\Omega\)
2. \(4~\Omega\)
3. \(2~\Omega\)
4. \(7~\Omega\)

The current in a wire varies with time according to the equation \(I=(4+2t),\) where \(I\) is in ampere and \(t\) is in seconds. The quantity of charge which has passed through a cross-section of the wire during the time \(t=2\) s to \(t=6\) s will be: