The maximum number of neutrons are present in the nuclei of
The complete symbol for the atom with the given atomic number (Z) and atomic mass (A) would be, respectively,
i. | Z = 17 , A = 35. |
ii. | Z = 92 , A = 233. |
iii. | Z = 4 , A = 9. |
1.
2.
3.
4.
Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm.
The frequency (ν) and wave number of this yellow light would be, respectively:
1. 517 x 1014 s-1 , 172 x 106 m-1
2. 6.17 x 1014 s-1 , 1.72 x 106 m-1
3. 4.17 x 1014 s-1 , 2.72 x 106 m-1
4. 5.17 x 1014 s-1 , 1.72 x 106 m-1
The energy of the photon with a frequency of 3×1015 Hz is :
1. 1.988 × J
2. 1.588 × J
3. 1.288 × J
4. 2.988 × J
A photon of wavelength 4 × 10–7 m strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of emission would be:
1. | 0.97 eV | 2. | 97 eV |
3. | 4.97 × eV | 4. | 5.84 × 105 eV |
The wavelength of the light emitted when the electron returns to the ground state in the H atom, from n = 5 to n = 1, would be: (The ground-state electron energy is –2.18 × 10-18 j)
1. Wavelength = 9.498 x 10-8 km
2. Wavelength = 12.498 x 10-8 m
3. Wavelength = 9.498 x 10-8 m
4. Wavelength = 9.498 x 10-8 cm
The possible values of n, l, and m for the electron present in 3d would be respectively:
1. n = 3, l = 1, m = – 2, – 1, 3, 1, 2
2. n = 3, l = 3, m = – 2, – 1, 0, 1, 2
3. n = 3, l = 2, m = – 2, – 1, 0, 1, 2
4. n = 5, l = 2, m = – 2, – 1, 0, 1, 2
The number of electrons in the species , are respectively:
1. 15, 2, 1
2. 15, 1, 2
3. 1, 2, 15
4. 2, 1, 15
Orbital that does not exist:
1. | 6p | 2. | 2s |
3. | 3f | 4. | 2p |
The set of quantum numbers which represent 3p is
1. n =1, l =0;
2, n = 3; l=1
3. n = 4; l =2;
4. n = 4; l = 3