\(10\) resistors each of \(10\) \(\Omega\) resistance when connected together give minimum equivalent resistance \(R_1\) and maximum equivalent resistance \(R_2\) among various possible combinations. 
So, \({R_2 \over R_1}\) is equal to:
1. \(1\)
2. \(100\)
3. \(200\)
4. \(10\)
 
Subtopic:  Combination of Resistors |
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What will be the most suitable combination of three resistors \(A=2~\Omega, B= 4~\Omega, C= 6~\Omega\) so that \(\left({22 \over 3}\right)\Omega\) is the equivalent resistance of combination? 
1. Parallel combination of \(A\) and \(C\) connected in series with \(B\)
2. Parallel combination of \(A\) and \(B\) connected in series with \(C\).
3. Series combination of \(A\) and \(C\) connected in parallel with \(B\)
4. Series combination of \(B\) and \(C\) connected in parallel with \(A\)
Subtopic:  Combination of Resistors |
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What is the equivalent resistance of the network shown in fig. between the points \(a\) and \(b\)?
                
1. \( 4 r \)
2. \( r / 4 \)
3. \( 3 r \)
4. \( r / 3\)
 
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Two resistors are connected in series, giving an equivalent resistance \(S.\) When the same resistors are connected in parallel, the equivalent resistance is \(P.\) If \(S= nP,\) what is the minimum value of \(n\text{?}\) (round off to the nearest integer)
1. \(4\)
2. \(7\)
3. \(9\)
4. \(2\)
Subtopic:  Combination of Resistors |
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In the given figure, the equivalent resistance between the points \(A\) and \(B\) is:

1. \(8~\Omega\)

2. \(6~\Omega\)

3. \(4~\Omega\)

4. \(2~\Omega\)
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The equivalent resistance between points \(A\) and \(B\) in the given network is:
        
1. \(65~\Omega\)
2. \(20~\Omega\)
3. \(5~\Omega\)
4. \(2~\Omega\)
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The effective resistance in the following circuit across terminal \(A\) and \(B\) is equal to:
     
1. \(5~ \Omega\) 2. \(10 ~\Omega\)
3. \(20~ \Omega\) 4. \(40~ \Omega\)
Subtopic:  Combination of Resistors |
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Two wires of equal diameter and of resistivity \(\rho_1\) and \(\rho_2\) and length \(x_1\) and \(x_2\) are joined in series. The equivalent resistivity of the combination is:
1. \(\dfrac{\rho_1x_1+\rho_2x_2}{x_1+x_2}\)
2. \(\dfrac{\rho_1x_2+\rho_2x_1}{x_1+x_2}\)
3. \(\dfrac{\rho_1x_1-\rho_2x_2}{x_1-x_2}\)
4. \(\dfrac{\rho_1x_2-\rho_2x_1}{x_1-x_2}\)
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A potential difference \(V_{AB}\) is impressed across \(AB\) and the potential difference across \(CD\) \((V_{CD})\) is measured. Assume, \(V_{AB}=300~\text{V}.\)


The current through the \(8~\Omega\) resistance is:
1. \(\dfrac{300}{17}~\text A\)
2. \(\dfrac{300}{8.5}~\text A\)
3.  \(30~\text A\)
4. \(\Big(\dfrac{300}{14}+\dfrac{300}{11}\Big)~\text A~~\)
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In the figure shown, what is the current (in Ampere) drawn from the battery? You are given \(R_1=15~ \Omega, R_2=10~ \Omega, R_3=20~ \Omega,R_4=5~ \Omega, R_5=25~ \Omega, R_6=30~ \Omega, E=15~V\)
  

1. \(7/18\)
2. \(20/3\)
3. \(9/32\)
4. \(13/24\)

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