A moving charge produces:
1. electric field only
2. magnetic field only
3. both of them
4. none of them

Subtopic:  Biot-Savart Law |
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To calculate the magnetic field due to a straight current-carrying conducting wire, at a nearby point, we use:
1. Fleming's left-hand rule 2. Biot-Savart law
3. Gauss's law 4. Lenz's law
Subtopic:  Biot-Savart Law |
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Biot-Savart law indicates that the moving electrons (velocity \(v\)) produce a magnetic field \(B\) such that:

1. \(B\perp v\).
2. \(B\parallel v\).
3. it obeys inverse cube law.
4. it is along the line joining the electron and point of observation.

Subtopic:  Biot-Savart Law |
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An element of length \(0.05{\hat i}~\text m\) is placed at the origin as shown in the figure and carries a current of \(10~\text{A}.\) The magnetic field at a point \(1~\text{m}\) away in a direction perpendicular to the element is:

1. \(4.5\times 10^{-8}~\text{T}\) 2. \(5.5\times 10^{-8}~\text{T}\)
3. \(5.0\times 10^{-8}~\text{T}\) 4. \(7.5\times 10^{-8}~\text{T}\)
Subtopic:  Biot-Savart Law |
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The strength of the magnetic field around a straight current-carrying conductor as observed by Biot and Savart was that:
1. field is the same every where around the conductor.
2. field is directly proportional to the square of the current flowing in the conductor.
3. field obeys the inverse square law of distance.
4. magnetic field strength was maximum on the axis of the current conductor.
Subtopic:  Biot-Savart Law |
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The magnetic induction due to an infinitely long straight wire carrying a current \(i\) at a distance \(r\) from the wire is given by:
1. \( B =\dfrac{\mu_0}{4 \pi} \dfrac{2 i}{r} \)
2. \(B =\dfrac{\mu_0}{4 \pi} \dfrac{r}{2 i} \)
3. \(B =\dfrac{4 \pi}{\mu_0} \dfrac{2 i}{r} \)
4. \(B =\dfrac{4 \pi}{\mu_0} \dfrac{r}{2 i}\)

Subtopic:  Magnetic Field due to various cases |
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A circular coil \(A \) has a radius \(R\) and the current flowing through it is \(I.\) Another circular coil \(B\) has a radius \(2R\) and if \(2I\) is the current flowing through it, then the magnetic fields at the centre of the circular coil are in the ratio of:
1. \(4:1\)                             
2. \(2:1\)
3. \(3:1\)                             
4. \(1:1\)

Subtopic:  Magnetic Field due to various cases |
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The magnetic induction at the centre \(O\) in the figure shown is:
1. \(\dfrac{\mu_0i}{4}\Big(\dfrac{1}{R_1}-\dfrac{1}{R_2}\Big)\) 2. \(\dfrac{\mu_0i}{4}\Big(\dfrac{1}{R_1}+\dfrac{1}{R_2}\Big)\)
3. \(\dfrac{\mu_0i}{4}({R_1}-{R_2})\) 4. \(\dfrac{\mu_0i}{4}({R_1}+{R_2})\)
Subtopic:  Magnetic Field due to various cases |
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A long wire carrying a steady current is bent into a circular loop of one turn. The magnetic field at the centre of the loop is \(B\). It is then bent into a circular coil of \(n\) turns. The magnetic field at the centre of this coil of \(n\) turns will be:
1. \(nB\)
2. \(n^2B\)
3. \(2nB\)
4. \(2n^2B\)
Subtopic:  Magnetic Field due to various cases |
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Level 1: 80%+
NEET - 2016
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In a long solenoid the magnetic field intensity inside the solenoid is equal to \(1.6 \times 10^{-3}~ T\). If number of turns per unit length on the solenoid is equal to \(8 \over \pi\) per cm then current flowing in the solenoid is equal to:
1. 5 A
2. 2.5 A
3. 7 A
4. 10 A
Subtopic:  Magnetic Field due to various cases |
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JEE
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