- 1(current)
Q. No.Polaroid glass is used in sun glasses because:
| 1. | it reduces the light intensity to half on account of polarisation |
| 2. | it is fashionable |
| 3. | it has good colour |
| 4. | it is cheaper |
Subtopic: Â Polarization of Light |
 96%
Level 1: 80%+
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Two polaroids are placed at an angle of \(45^\circ\) to each other. If an unpolarized light of intensity \(I_0\) falls as one polaroid, then the intensity of light leaves the second polaroid is:
| 1. | \(\dfrac{I_0}{2}\) | 2. | \(\dfrac{I_0}{2 \sqrt{2}}\) |
| 3. | \(\dfrac{I_0}{4} \) | 4. | \( \dfrac{I_0}{8}\) |
Subtopic: Â Polarization of Light |
 80%
Level 1: 80%+
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Unpolarised light of intensity \(X\) is incident on a polarising sheet. A second polaroid whose pass-axis makes an angle \(30^\circ\) with the pass-axis of the first polaroid is kept behind it. The intensity of the light that gets transmitted after the second polaroid is:
| 1. | \(X\) | 2. | \(\dfrac{3X}{8}\) |
| 3. | \(\dfrac{X}{4}\) | 4. | \(\dfrac{X}{2}\) |
Subtopic: Â Polarization of Light |
 80%
Level 1: 80%+
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An unpolarised light beam of intensity \(2I_0\) is passed through a polaroid \(P\) and then through another polaroid \(Q\) which is oriented in such a way that its passing axis makes an angle of \(30^{\circ}\) relative to that of \(P\). The intensity of the emergent light is:
1. \(\dfrac{I_0}{4} \)
2. \(\dfrac{I_0}{2} \)
3. \(\dfrac{3 I_0}{4} \)
4. \(\dfrac{3 I_0}{2}\)
1. \(\dfrac{I_0}{4} \)
2. \(\dfrac{I_0}{2} \)
3. \(\dfrac{3 I_0}{4} \)
4. \(\dfrac{3 I_0}{2}\)
Subtopic: Â Polarization of Light |
 80%
Level 1: 80%+
JEE
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Two polarisers \(P_1\) and \(P_2\) are placed such that the angle between their transmission axis is \(45^{\circ}\). Ordinary light is passed through \(P_1,\) \(I_1\) intensity is observed and when this light is passed through \(P_2,\) \(I_2\) intensity is observed. The ratio of \(\dfrac{I_1}{I_2}\) is:
| 1. | \(\dfrac{4}{3}\) | 2. | \(\dfrac{3}{4}\) |
| 3. | \(2\) | 4. | \(\dfrac{1}{2}\) |
Subtopic: Â Polarization of Light |
 79%
Level 2: 60%+
JEE
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A beam of unpolarised light of intensity \(I_0\) is passed through a polaroid \(A,\) through another polaroid \(B,\) oriented at \(60^\circ\) and finally through another polaroid \(C,\) oriented at \(45^\circ\) relative to \(B\) as shown in the figure. The intensity of the emergent light is:
| 1. | \(\dfrac{{I}_0}{16}\) | 2. | \(\dfrac{{I}_0}4\) |
| 3. | \(\dfrac{{I}_0}2\) | 4. | \(\dfrac{{I}_0}{32}\) |
Subtopic: Â Polarization of Light |
 78%
Level 2: 60%+
NEET - 2024
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Which of the following phenomena cannot be explained using the wave theory of light?
Choose the correct option from the given ones:
| (A) | Reflection |
| (B) | Diffraction |
| (C) | Photoelectric effect |
| (D) | Interference |
| (E) | Polarisation |
Choose the correct option from the given ones:
| 1. | (E) only | 2. | (A), (C) only |
| 3. | (B), (D) only | 4. | (C) only |
Subtopic: Â Polarization of Light |
 63%
Level 2: 60%+
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Given below are two statements:
| Assertion (A): | Radio waves can be polarised. |
| Reason (R): | Sound waves in the air are longitudinal in nature. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
Subtopic: Â Polarization of Light |
 76%
Level 2: 60%+
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The Brewster's angle for an interface should be:
1. \(30^{\circ}<i_b<45^{\circ}\)
2. \(45^{\circ}<i_b<90^{\circ}\)
3. \(i_b=90^{\circ}\)
4. \(0^{\circ}<i_b<30^{\circ}\)
Subtopic: Â Polarization of Light |
 75%
Level 2: 60%+
NEET - 2020
Hints
- 1(current)
Q. No.
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