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Q. No.According to Einstein's photoelectric equation, the graph between the kinetic energy of photoelectrons ejected and the frequency of incident radiation is:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Subtopic: Einstein's Photoelectric Equation |
77%
From NCERT
AIPMT - 2004
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The threshold frequency of a photoelectric metal is \(\nu_0.\) If the light of frequency \(4\nu_0\) is incident on this metal, then the maximum kinetic energy of emitted electrons will be:
| 1. | \(h\nu_0\) | 2. | \(2h\nu_0\) |
| 3. | \(3h\nu_0\) | 4. | \(4h\nu_0\) |
Subtopic: Einstein's Photoelectric Equation |
83%
From NCERT
NEET - 2022
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The work function of caesium is \(2.14~\text{eV}\). The wavelength of incident light if the photocurrent is brought to zero by a stopping potential of \(0.60~\text{V}\) will be:
1. \(454~\text{nm}\)
2. \(440~\text{nm}\)
3. \(333~\text{nm}\)
4. \(350~\text{nm}\)
Subtopic: Einstein's Photoelectric Equation |
61%
From NCERT
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The light rays having photons of energy \(4.2~\text{eV}\) are falling on a metal surface having a work function of \(2.2~\text{eV}.\) The stopping potential of the surface is:
| 1. | \(2~\text{eV}\) | 2. | \(2~\text{V}\) |
| 3. | \(1.1~\text{V}\) | 4. | \(6.4~\text{V}\) |
Subtopic: Einstein's Photoelectric Equation |
64%
From NCERT
NEET - 2022
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The electric field associated with a light wave is given by \(E = E_0~ (\sin \omega_1 t)~ (\sin \omega_2 t)\).
This light wave falls on a metal having a threshold frequency, \(\nu_o.\) The maximum kinetic energy of the emitted photoelectrons will be: (\(h\) is Planck's constant)
This light wave falls on a metal having a threshold frequency, \(\nu_o.\) The maximum kinetic energy of the emitted photoelectrons will be: (\(h\) is Planck's constant)
| 1. | Either \(\frac{h \omega_{1}}{2 \pi}\) or \(\frac{h \omega_{2}}{2 \pi}\) |
| 2. | Either\(\left(\frac{h \omega_{1}}{2 \pi}-h \nu_{0}\right)\) or \(\left(\frac{h \omega}{2 \pi}-h \nu_{0}\right)\) |
| 3. | \(\frac{h\left(\omega_{1}+\omega_{2}\right)}{2 \pi}-h \nu_{0}\) |
| 4. | Both \(\frac{h\left(\omega_{1}+\omega_{2}\right)}{2 \pi}-h \nu_{0}\) and \(\frac{h\left |\omega_{1}-\omega_{2}\right|}{2 \pi}-h \nu_{0}\) |
Subtopic: Einstein's Photoelectric Equation |
51%
From NCERT
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Light of wavelength \(4000~\mathring{A}\) is incident on a metal whose work function is \(2.0\) eV. The fastest photo-electrons emitted have an energy of:
(Take \(hc=12400\) eV-\(\mathring A\))
1. \(0.5\) eV
2. \(3.1\) eV
3. \(1.1\) eV
4. \(2\) eV
(Take \(hc=12400\) eV-\(\mathring A\))
1. \(0.5\) eV
2. \(3.1\) eV
3. \(1.1\) eV
4. \(2\) eV
Subtopic: Einstein's Photoelectric Equation |
82%
From NCERT
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When a metallic surface is illuminated with radiation of wavelength \(\lambda\), the stopping potential is \({V}\). If the same surface is illuminated with radiation of wavelength \(2\lambda\), the stopping potential is \(\frac{{V}}{4}\). The threshold wavelength for the metallic surface is:
1. \(5\lambda\)
2. \(\frac{5}{2} \lambda\)
3. \(3\lambda\)
4. \(4\lambda\)
1. \(5\lambda\)
2. \(\frac{5}{2} \lambda\)
3. \(3\lambda\)
4. \(4\lambda\)
Subtopic: Einstein's Photoelectric Equation |
76%
From NCERT
NEET - 2016
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