The quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline with 50 % current efficiency is:

1. 1 F

2. 0.6 F

3. 0.5 F

4. 1.2 F

Subtopic:  Faraday’s Law of Electrolysis |
Level 3: 35%-60%
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When aqueous NaCl solution is electrolysed using inert electrodes then pH of the solution:

1. Increases.

2. Decreases.

3. Remains same.

4. First increases then decreases.

Subtopic:  Electrolytic & Electrochemical Cell |
 61%
Level 2: 60%+
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Find the maximum electrical work obtainable from the Daniell cell:

Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s)

Given:

E°(Zn²⁺/Zn) = −0.76 V
E°(Cu²⁺/Cu) = +0.34 V

\(E^o_{Zn^{2+}/Zn}\) −0.76 V
\(E^o_{Cu^{2+}/Cu}\) 0.34 V

1. +106.15 kJ

2. -212.3 kJ

3. -424.6 kJ

4. +212.3 kJ

Subtopic:  Electrode & Electrode Potential |
 63%
Level 2: 60%+
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Calculate the EMF of the following concentration cell at 298 K:

Pt | H₂(1 atm) | H⁺(0.02 M) || H⁺(0.01 M) | H₂(1 atm) | Pt

1. - 0.017 V

2. 0.0295 V

3. 0.10 V

4. 0.059 V

Subtopic:  Nernst Equation |
 63%
Level 2: 60%+
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By how much will the electrode potential of the Cu²⁺/Cu half-cell change when the concentration of Cu²⁺ ions is reduced to one-hundredth of its initial value at 298 K?

1. Increase by 59 mV 2. Decrease by 59 mV
3. Increase by 29.5 mV 4. Decrease by 29.5 mV
Subtopic:  Nernst Equation |
 58%
Level 3: 35%-60%
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Find the relationship between E₁ and E₂ for the following Daniell cell:

Zn | ZnSO₄ (0.01 M) || CuSO₄ (1.0 M) | Cu

The emf of this cell is E₁.

If the concentration of ZnSO₄ is changed to 1.0 M and that of CuSO₄ is changed to 0.01 M, the emf becomes E₂.

Given:

RT/F = 0.059 V

1. E1 = E2

2. E1 > E2

3. E1 < E2

4. E2 = 0 \(\neq\)E1

Subtopic:  Electrode & Electrode Potential | Nernst Equation |
Level 4: Below 35%
NEET - 2017
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The weight of silver (atomic weight = 108) displaced by a quantity of electricity which displaces 5600 mL of O2 at STP will be : 

1. 5.4 g

2. 10.8 g

3. 54.0 g

4. 108.0 g

Subtopic:  Faraday’s Law of Electrolysis |
 54%
Level 3: 35%-60%
NEET - 2014
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Given the reaction:

\(\mathrm{Cu}(\mathrm{~s})+2 \mathrm{Ag}^{+}(\mathrm{aq}) \rightarrow \mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{~s})\) with E° = 0.46 V at 298 K,
what is the equilibrium constant for the reaction?

1. 2.4 x 1010 2. 2.0 x 1010
3. 4.0 x 1010 4. 4.0 x 1015
Subtopic:  Relation between Emf, G, Kc & pH |
 69%
Level 2: 60%+
NEET - 2007
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During electrolysis of conc. H2SO4, perdisulphuric acid (H2S2O8), and O2
form in equimolar amount. The amount of H2 that will form simultaneously will be : 

1. Thrice that of O2 in moles.

2. Twice that of O2 in moles.

3. Equal to that of O2 in moles.

4. Half of that of O2 in moles.

Subtopic:  Faraday’s Law of Electrolysis |
Level 3: 35%-60%
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What happens to the voltage in a galvanic cell when the salt bridge is removed?

1. The voltage drops to zero.
2. The voltage remains the same.
3. The voltage gradually increases.
4. The voltage rapidly increases.

Subtopic:  Batteries & Salt Bridge |
 79%
Level 2: 60%+
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