In the organic compound, the pair of hydridized orbitals involved in the formation of C2 – C3 bond is-
1. sp –
2. sp –
3. –
4. –
The number of σ and π bonds in the molecule are -
1. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
2. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
3. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
4. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
The number of σ and π bonds in the molecule are:
1. 7 = ( , 11 = , and 0= π
2. 6 = ( , 12 = , and 0= π
3. 12 = ( , 6 = , and 1= π
4. 5 = ( , 13 = , and 1= π
The correct hybridization states of carbon atoms in the above compound are -
1. | C1= sp , C2= sp3 | 2. | C1= sp2 , C2= sp |
3. | C1= sp3 , C2= sp | 4. | C1= sp , C2= sp2 |
The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are -
1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C3= sp3 |
3. | C1= sp3 , C2= sp2 , C3= sp2 | 4. | C1= sp3 , C2= sp3 , C3= sp3 |
The correct hybridization of carbon atoms are:
1. C1= sp , C2= sp3 , C2= sp2
2. C1= sp2 , C2= sp3 , C2= sp3
3. C1= sp3 , C2= sp2 , C2= sp3
4. C1= sp3 , C2= sp3 , C2= sp3
The correct hybridization states of carbon atoms in the following compound are -
1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C 3 = sp3 |
3. | C1= sp2 , C2= sp2 , C 3 = sp | 4. | C1= sp3 , C2= sp3 , C 3 = sp3 |
The correct hybridization states of carbon atoms in C6H6 is/are:
1. sp2
2. sp
3. sp3
4. All of the above