Free radical formation will take place in :
1. | |
2. | |
3. | |
4. |
The effect that can explain the given order of acidity of the carboxylic acids is-
Cl3CCOOH > Cl2CHCOOH > ClCH2COOH
1. +I effect
2. -I effect
3. +E effect
4. -E effect
The purification method based on the difference in solubilities of the compound and the impurities in a solvent is -
1. Crystallisation
2. Distillation
3. Chromatography
4. Isolation
The 3° carbon atom in the given structure is :
1. a
2. b
3. c
4. e
Elimination reaction among the following is-
1. | CH 3 CH 2 Br + HS - → CH 3 CH 2 SH + Br - | 2. | ( CH 3 ) 2 C = CH 2 + HCl → ( CH 3 ) 2 ClC - CH 3 |
3. | CH 3 CH 2 Br + HO - → CH 2 = CH 2 + Br - + H 2 O | 4. | ( CH 3 ) 3 C - CH 2 OH + HBr → ( CH 3 ) 2 CBrCH 2 CH 3 + H 2 O |
An electrophile among the following is -
1. | \(\mathrm{OH}^-\) | 2. | \(\mathrm{NC}^-\) |
3. | \(R_3C^-\) | 4. | Carbonyl group |
Alkyl groups act as electron donors when attached to a π system due to-
1. Inductive effect
2. Mesomeric effect
3. Resonance
4. Hyperconjugation
is more stable than because :
1. | NO2 shows +I effect |
2. | NO2 shows -I effect |
3. | NO2 decreases the positive charge on the compound |
4. | Ethyl group increases positive charge on the compound |
The most stable carbocation among the following is-
1. \(({CH_3})_3C\overset{+}{C}H_2\)
2. \(({CH_3})_3\overset{+}{C}\)
3. \({CH_3}CH_2\overset{+}{C}H_2\)
4. \(({CH_3})\overset{+}{C}HCH_2CH_3\)