In the preparation of compounds of Xe, Bartlett had taken as a base compound. This is because:
1. | Both O2 and Xe have the same size. |
2. | Both O2 and Xe have the same electron gain enthalpy. |
3. | Both O2 and Xe have almost the same ionisation enthalpy. |
4. | Both Xe and O2 are gases. |
Which of the following statements is/are true?
a. | Only types of interactions between particles of noble gases are due to weak dispersion forces. |
b. | The ionization enthalpy of molecular oxygen is very close to that of xenon. |
c. | Hydrolysis of XeF6 is a redox reaction. |
d. | Xenon fluorides are not reactive. |
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, d)
Match the compounds given in Column I with the hybridisation and shape given in Column II and mark the correct option.
Column I | Column II | ||
A | XeF6 | 1. | sp3d3 distorted octahedral |
B. | XeO3 | 2. | sp3d2 square planar |
C. | XeOF4 | 3. | sp3 pyramidal |
D. | XeF4 | 4. | sp3d2 square pyramidal |
Codes:
Options: | A | B | C | D |
1. | 1 | 3 | 4 | 2 |
2. | 1 | 2 | 4 | 3 |
3. | 4 | 3 | 1 | 2 |
4. | 4 | 1 | 2 | 3 |
Match the species given in Column I with the shape given in Column II and mark the correct option.
Column I | Column II | ||
A. | Its partial hydrolysis does not change the oxidation state of the central atom. | 1. | He |
B. | It is used in modern diving apparatus. | 2. | XeF6 |
C. | It is used to provide an inert atmosphere for filling electrical bulbs. | 3. | XeF4 |
D. | Its central atom is in sp3d2 hybridisation. | 4. | Ar |
Codes:
Options: | A | B | C | D |
1. | 1 | 4 | 2 | 3 |
2. | 1 | 2 | 3 | 4 |
3. | 2 | 1 | 4 | 3 |
4. | 1 | 3 | 2 | 4 |