1. | The acidic strength of HX (X=F, Cl, Br and I) follows the order: HF > HCI > HBr >HI |
2. | Fluorine exhibits - 1 oxidation state whereas other halogens exhibit +1, +3, +5 and +7 oxidation states also. |
3. | The enthalpy of dissociation of F2 is smaller than that of Cl2. |
4. | Fluorine is stronger oxidising agent than chlorine. |
Assertion (A): | ICl is more reactive than I₂. |
Reason (R): | I-Cl bond is weaker than I-I bond. |
1. | (A) is False but (R) is True. |
2. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
3. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
4. | (A) is True but (R) is False. |
Chlorine shows the bleaching action in the presence of moisture due to the formation of
1. HOCl
2. HOClO
3. H2O2
4. O
(a) | F–F bond has a low enthalpy of dissociation. |
(b) | Flouride ion (F–) has high hydration enthalpy. |
(c) | Electron gain enthalpy of fluorine is less negative than chlorine. |
(d) | Fluorine has a very small size. |
1. | (a) and (b) only | 2. | (a) and (c) only |
3. | (a) and (d) only | 4. | (b) and (c) only |
Statement I: | Acid strength increases in the order given as HF < HCl < HBr < HI. |
Statement II: | As the size of the elements F, Cl, Br, I increases down the group, the bond strength of HF, HCI, HBr, and HI decreases and so the acid strength increases. |
1. | Statement I is correct and Statement II is incorrect | |
2. |
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3. | Both Statement I and Statement II are correct. | |
4. | Both Statement I and Statement II are incorrect. |
Choose the pairs of isoelectronic compounds which are isostructural:
1. TeF2, XeF2
2. IBr2-, XeF2
3. IF3, XeF2
4. BeCl2, XeF2
Which of the statements given below is incorrect?
1. \(\mathrm{C l_{2} O_{7 }}\)is an anhydride of perchloric acid
2. \(\mathrm{O_{3}}\) molecule is bent
3. ONF is isoelectronic with \(\mathrm{N O_{2}^{-}}\)
4. \(\mathrm{O F_{2}}\) is an oxide of fluorine
The variation of the boiling point of the hydrogen halides is in the order HF > HI > HBr > HCl.
The higher boiling point of hydrogen fluoride is explained as:
1. | The electronegativity of flourine is much higher than other elements in group |
2. | There is strong hydrogen bonding between HF molecules |
3. | The bond energy of HF molecules is greater than in other hydrogen halides |
4. | The effect of nuclear shielding is much reduced in flourine which polarizes the HF molecule |