Match List I with List II.
List I
(Conversion)
List II
(Number of Faraday required)
A. 1 mol of H2O to O2 I. 3F
B. 1 mol of \(MnO^-_4\) to \(Mn^{2+}\) II. 2F
C. 1.5 mol of \(Ca\) from molten \(CaCl_2\) III. 1F
D. 1 mol of FeO to Fe2O3 IV. 5F
Choose the correct answer from the options given below:
1. A - III, B - IV, C - I, D - II
2. A - II, B - III, C - I, D - IV
3. A - III, B - IV, C - II, D - I
4. A - II, B - IV, C - I, D - III
Subtopic:  Faraday’s Law of Electrolysis |
 65%
From NCERT
NEET - 2024
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Mass in grams of copper deposited by passing 9.6487 A current through a voltmeter containing copper sulphate for 100 seconds is(Given : Molar mass of Cu: \(63 g mol^{-1}\) F = 96487 C) 

1. 0.315 g 
2. 31.5 g 
3. 0.0315 g 
4. 3.15 g 
Subtopic:  Faraday’s Law of Electrolysis |
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From NCERT
NEET - 2024
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Given below are two statements:
Statement I: \(2 \mathrm{~F}\) electricity is required for the oxidation of 1 mole \(\mathrm{H}_2 \mathrm{O}\) to \(\mathrm{O}_2\).
Statement II: To get \(40.0 \mathrm{~g}\) of Aluminium from molten \(\mathrm{Al}_2 \mathrm{O}_3\) required electricity is \(4.44 \mathrm{~F}\).

In the light of the above statements, choose the correct answer from the options given below:
1. Both Statement I and Statement II are true
2. Both Statement I and Statement II are false
3. Statement I is true but Statement II is false
4. Statement I is false but Statement II is true
Subtopic:  Faraday’s Law of Electrolysis |
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From NCERT
NEET - 2024
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R):
Assertion (A): In equation \(\Delta_{\mathrm{r}} \mathrm{G}=-\mathrm{nFE} _{\text {cell }}, \) value \(\mathrm{\Delta_rG }\) depends on n. 
Reason (R): \(\mathrm{E_{cell} }\) is an intensive property and \(\mathrm{\Delta_rG }\)  is an extensive property. 
 
In the light of the above statements choose the correct answer from the options given below: 
 
1. (A) is False but (R) is True. 
2. Both (A) and (R) are True and (R) is the correct explanation of (A)
3. Both (A) and (R) are True and (R) is not the correct explanation of (A)
4. (A) is True but (R) is False.
Subtopic:  Relation between Emf, G, Kc & pH |
 57%
From NCERT
NEET - 2023
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The conductivity of centimolar solution of KCl at 25°C is 0.0210 ohm–1 cm–1 and the resistance of the cell containing the solution at 25°C is 60 ohm. The value of the cell constant is: 
1. 3.34 cm–1 2. 1.34 cm–1
3. 3.28 cm–1 4. 1.26 cm–1
Subtopic:  Conductance & Conductivity |
 77%
From NCERT
NEET - 2023
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The molar conductance of an electrolyte increases with dilution according to the equation: 
\(\Lambda_{\mathrm{m}}=\Lambda_{\mathrm{m}}^{\circ}-\mathrm{A} \sqrt{\mathrm{c}} \)
Consider the following four statements:
A: This equation applies to both strong and weak electrolytes.
B: The value of the constant A depends upon the nature of the solvent. 
C: The value of constant A is the same for both \(BaCl_2\) and \(MgSO_4\)
D: The value of constant A is the same for both \(BaCl_2\) and \(Mg(OH)_2\)
Which of the above statements are correct? 
1. (A) and (B) only 
2. (A), (B), and (C) only 
3. (B) and (C) only 
4. (B) and (D) only 
Subtopic:  Conductance & Conductivity |
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From NCERT
NEET - 2023
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The correct value of cell potential in volt for the reaction that occurs when the following two half cells are connected, is:
\(\mathrm{Fe}_{\text {(aq) }}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Fe}(\mathrm{s}), \mathrm{E}^{\circ}=-0.44 \mathrm{~V} \)
\( \mathrm{Cr}_2 \mathrm{O}_7^{2-}{ }_{\text {(aq) }}+14 \mathrm{H}^{+}+6 e^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_2 \mathrm{O},\)
\( \mathrm{E}^{\circ}=+1.33 \mathrm{~V}\)
1. +1.77 V 2. +2.65 V 
3. +0.01 V  4. +0.89 V
Subtopic:  Electrode & Electrode Potential |
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From NCERT
NEET - 2023
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The molar conductance of a solution, given its conductivity (0.248 S m–1) and concentration (0.2 mol m–3) is:
1. 0.124 S cm2 mol–1
2. 1.24 S mmol–1
3. 124 S cm2 mol–1
4. 124 S m2 mol–1
Subtopic:  Conductance & Conductivity |
From NCERT
NEET - 2023
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Given below are half-cell reactions:
\(\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}, \)
\( \mathrm{E}_{\mathrm{Mn}^{2+}}^{\circ} / \mathrm{MnO}_{4}^{-}=-1.510 \mathrm{~V} \)
\( \frac{1}{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}, \)
\( \mathrm{E}_{\mathrm{O}_{2} / \mathrm{H}_{2} \mathrm{O}}^{\circ}=+1.223 \mathrm{~V}\)
Will the permanganate ion, \(\mathrm{MnO}_{4}^{-}\) , liberate \(\mathrm{O}_{2}\) from water in the presence of an acid?

1. No, because \(\mathrm{E}_{\text {cell }}^{\circ}=-2.733 \mathrm{~V}\)
2. Yes, because \(\mathrm{E}_{\text {cell }}^{\circ}=+0.287 \mathrm{~V}\)
3. No, because \(\mathrm{E}_{\text {cell }}^{\circ}=-0.287 \mathrm{~V}\)
4. Yes, because \(\mathrm{E}_{\text {cell }}^{\circ}=+2.733 \mathrm{~V}\)
Subtopic:  Electrode & Electrode Potential |
From NCERT
NEET - 2022
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Find the emf of the cell in which the following reaction takes place at 298 K:
\(\mathrm{Ni}(\mathrm{s})+2 \mathrm{Ag}^{+}(0.001 \mathrm{M}) \rightarrow \mathrm{Ni}^{2+}(0.001 \mathrm{M})+2 \mathrm{Ag}(\mathrm{s}) \)
\( \small{\text { (Given that } \mathrm{E}_{\text {cell }}^{\circ}=10.5 \mathrm{~V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \text { at } \ 298 \mathrm{~K})} \)
1. 1.05 V
2. 1.0385 V 
3. 1.385 V
4. 0.9615 V 

Subtopic:  Nernst Equation |
From NCERT
NEET - 2022
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