Statement I: | The energy of the \(\mathrm{He}^{+}\) ion in \(n=2\) state is same as the energy of H atom in \(n=1\) state |
Statement II: | It is possible to determine simultaneously the exact position and exact momentum of an electron in \(\mathrm{H}\) atom. |
List I Quantum Number |
List II Information provided |
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A. | ml | I. | shape of orbital |
B. | ms | II. | size of orbital |
C. | l | III. | orientation of orbital |
D. | n | IV. | orientation of spin of electron |
I: | \(\Psi\) depends upon the coordinates of the electron in the atom | The value of wave function,
II: | The probability of finding an electron at a point within an atom is proportional to the orbital wave function |
List-I (quantum number) |
List-II (Orbital) |
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(A) | n = 2, \(\ell\) = 1 | (I) | 2s |
(B) | n = 3, \(\ell\) = 2 | (II) | 3s |
(C) | n = 3, \(\ell\) = 0 | (III) | 2p |
(D) | n = 2, \(\ell\) = 0 | (IV) | 3d |
(A) | (B) | (C) | (D) | |
1. | (III) | (IV) | (I) | (II) |
2. | (IV) | (III) | (I) | (II) |
3. | (IV) | (III) | (II) | (I) |
4. | (III) | (IV) | (II) | (I) |
A monochromatic infrared range finder of power 1milli watt emits photons with wavelength 1000 nm in 0.1 second. The number of photons emitted in 0.1 second is:
(Given: h = \(6.626 \times 10^{-34} J~s\) , c = \(3 \times 10^8 m~s^{-1}, \) Avogadro number = \(6.022 \times 10^{23}\))
1. \(30 \times 10^{37}\)
2. \(5 \times 10^{14} \)
3. \(30 \times 10^{34} \)
4. \(5 \times 10^{11} \)