- 1(current)
Q. No.The amount of glucose required to prepare 250 mL of \(\frac{M}{20}\) aqueous solution is:
(Molar mass of glucose: 180 g \(\mathrm{mol ^{-1}}\))
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
(Molar mass of glucose: 180 g \(\mathrm{mol ^{-1}}\))
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
Subtopic: Concentration Based Problem |
From NCERT
NEET - 2024
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Mass of glucose \(\left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)\) required to be dissolved to prepare one litre of its solution which is isotone with \(15~g~L^{-1}\) solution of urea \(\mathrm{(NH_2 CONH_2)}\) is:
(Given : Molar mass in g \(\mathrm{mol}^{-1}\) C:12, H:1, O: 16, N:14 )
1. 55 g
2. 15 g
3. 30 g
4. 45 g
(Given : Molar mass in g \(\mathrm{mol}^{-1}\) C:12, H:1, O: 16, N:14 )
1. 55 g
2. 15 g
3. 30 g
4. 45 g
Subtopic: Concentration Based Problem |
From NCERT
NEET - 2024
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The density of 1 M solution of a compound 'X' is 1.25 g mL–1. The correct option for the molality of solution is:
(Molar mass of compound X = 85 g):
(Molar mass of compound X = 85 g):
| 1. | 0.705 m | 2. | 1.208 m |
| 3. | 1.165 m | 4. | 0.858 m |
Subtopic: Concentration Based Problem |
64%
From NCERT
NEET - 2023
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The density of a 2 M aqueous solution of NaOH is 1.28 g/. The molality of the solution is:
[molecular mass of NaOH = 40 ]
| 1. | 1.20 m | 2. | 1.56 m |
| 3. | 1.67 m | 4. | 1.32 m |
Subtopic: Concentration Based Problem |
70%
From NCERT
NEET - 2019
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NEET 2025 - Target Batch
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NEET 2025 - Target Batch
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