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Q. No.1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to :
1. 250 mg
2. Zero mg
3. 200 mg
4. 750 mg
Subtopic: Millimole/Equivalent Concept |
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NEET - 2024
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A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is :
( Given atomic mass of A=64; B=40; C=32u)
1. ABC3
2. AB2C2
3. ABC4
4. A2BC2
( Given atomic mass of A=64; B=40; C=32u)
1. ABC3
2. AB2C2
3. ABC4
4. A2BC2
Subtopic: Empirical & Molecular Formula |
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NEET - 2024
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4.74 g of an inorganic compound contains 0.39g of K, 0.27 g Al, 1.92 g of \(\mathrm{SO_4}\) radicals and 2.16 g of water. If molar mass of the compound is \(948 \mathrm{~g} \mathrm{~mol}^{-1},\) the molecular formula of the inorganic compound is:
| 1. | \(\mathrm{KAl}\left(\mathrm{SO}_4\right)_2 \cdot 12 \mathrm{H}_2 \mathrm{O}\) |
| 2. | \(\mathrm{K}_2 \mathrm{Al}_2\left(\mathrm{SO}_4\right)_6 \cdot 12 \mathrm{H}_2 \mathrm{O}\) |
| 3. | \(\mathrm{K}_2 \mathrm{SO}_4 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot24 \mathrm{H}_2 \mathrm{O}\) |
| 4. | \(\mathrm{K}_2 \mathrm{SO}_6 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot12 \mathrm{H}_2 \mathrm{O}\) |
Subtopic: Empirical & Molecular Formula |
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NEET - 2024
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Molar mass of a compound \(\text{(X)}\) whose \(2.6 \mathrm{~mol}\) weighs \(312 \mathrm{~g}\) is:
1. \(312 \mathrm{~g} \mathrm{~mol}^{-1}\)
2. \(120 \mathrm{~g} \mathrm{~mol}^{-1}\)
3. \(60 \mathrm{~g} \mathrm{~mol}^{-1}\)
4. \(811.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
1. \(312 \mathrm{~g} \mathrm{~mol}^{-1}\)
2. \(120 \mathrm{~g} \mathrm{~mol}^{-1}\)
3. \(60 \mathrm{~g} \mathrm{~mol}^{-1}\)
4. \(811.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
Subtopic: Empirical & Molecular Formula |
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NEET - 2024
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Which of the following contains the highest number of helium atoms?
1. 4 u of helium
2. 4 g of helium
3. 2.27 L of helium at STP
4. 4 mol of helium
1. 4 u of helium
2. 4 g of helium
3. 2.27 L of helium at STP
4. 4 mol of helium
Subtopic: Moles, Atoms & Electrons |
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NEET - 2024
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The amount of glucose required to prepare 250 mL of \(\frac{M}{20}\) aqueous solution is:
(Molar mass of glucose: 180 g \(\mathrm{mol ^{-1}}\))
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
(Molar mass of glucose: 180 g \(\mathrm{mol ^{-1}}\))
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
Subtopic: Concentration Based Problem |
From NCERT
NEET - 2024
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1.0 g of \(H_2\) has same number of molecules as in:
1. 14 g of \(N_2\)
2. 18 g of \(H_2O\)
3. 16 g of CO
4. 28 g of \(N_2\)
1. 14 g of \(N_2\)
2. 18 g of \(H_2O\)
3. 16 g of CO
4. 28 g of \(N_2\)
Subtopic: Moles, Atoms & Electrons |
From NCERT
NEET - 2024
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Mass of glucose \(\left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)\) required to be dissolved to prepare one litre of its solution which is isotone with \(15~g~L^{-1}\) solution of urea \(\mathrm{(NH_2 CONH_2)}\) is:
(Given : Molar mass in g \(\mathrm{mol}^{-1}\) C:12, H:1, O: 16, N:14 )
1. 55 g
2. 15 g
3. 30 g
4. 45 g
(Given : Molar mass in g \(\mathrm{mol}^{-1}\) C:12, H:1, O: 16, N:14 )
1. 55 g
2. 15 g
3. 30 g
4. 45 g
Subtopic: Concentration Based Problem |
From NCERT
NEET - 2024
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The density of 1 M solution of a compound 'X' is 1.25 g mL–1. The correct option for the molality of solution is:
(Molar mass of compound X = 85 g):
(Molar mass of compound X = 85 g):
| 1. | 0.705 m | 2. | 1.208 m |
| 3. | 1.165 m | 4. | 0.858 m |
Subtopic: Concentration Based Problem |
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NEET - 2023
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Select the correct statements from the following:
Choose the correct answer from the option given below:
| A: | Atoms of all elements are composed of two fundamental particles. |
| B: | The mass of the electron is \(9.10939 \times 10^{-31} \mathrm{~kg} \text {. }\). |
| C: | All the isotopes of a given element show same chemical properties. |
| D: | Protons and electrons are collectively known as nucleons. |
| E: | Dalton's atomic theory regarded the atom as an ultimate particle of matter. |
| 1. | B, C and E only | 2. | A, B and C only |
| 3. | C, D and E only | 4. | A and E only |
Subtopic: Introduction |
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NEET - 2023
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