In the given figure, the value of \(V_{0}\) will be: 
           
1. \(2\) V
2. \(4\) V
3. \(6\) V
4. \(3\) V
Subtopic:  Kirchoff's Voltage Law |
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Kirchhoff's second law is based on the law of conservation of:
1. charge
2. energy
3. momentum
4. sum of mass and energy
Subtopic:  Kirchoff's Voltage Law |
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The potential difference \(V_\mathrm{A}-V_\mathrm{B}\) between the points \(\mathrm{A}\) and \(\mathrm{B}\) in the given figure is:
    

1. \(-3~\text{V}\) 2. \(+3~\text{V}\)
3. \(+6~\text{V}\) 4. \(+9~\text{V}\)

Subtopic:  Kirchoff's Voltage Law |
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In the following circuit, the battery \(E_1\) has an emf of \(12\) volts and zero internal resistance while the battery \(E\) has an emf of \(2\) volts. If the galvanometer \(G\) reads zero, then the value of the resistance \(X\) in ohms is:

1. \(10\) 2. \(100\)
3. \(500\) 4. \(200\)
Subtopic:  Kirchoff's Voltage Law |
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Twelve wires of equal resistance \(R\) are connected to form a cube. The effective resistance between two diagonal ends \(A\) and \(E\) will be:

1. \(\dfrac{5 R}{6}\) 2. \(\dfrac{6 R}{5}\)
3. \(12 R\) 4. \(3 R\)
Subtopic:  Kirchoff's Voltage Law |
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See the electrical circuit shown in this figure. Which of the following is a correct equation for it?
                

1. \(\varepsilon_1-(i_1+i_2)R-i_1r_1=0\)
2. \(\varepsilon_2-i_2r_2-\varepsilon_1-i_1r_1=0\)
3. \(-\varepsilon_2-(i_1+i_2)R+i_2r_2=0\)
4. \(\varepsilon_1-(i_1+i_2)R+i_1r_1=0\)

Subtopic:  Kirchoff's Voltage Law |
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The current through the \(5~\Omega\) resistor is:

1. \(3.2\) A 2. \(2.8\) A
3. \(0.8\) A 4. \(0.2\) A
Subtopic:  Kirchoff's Voltage Law |
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For the circuit given below, Kirchhoff's loop rule for the loop \(BCDEB\) is given by the equation:

1. \(-{i}_2 {R}_2+{E}_2-{E}_3+{i}_3{R}_1=0\)
2. \({i}_2{R}_2+{E}_2-{E}_3-{i}_3 {R}_1=0\)
3. \({i}_2 {R}_2+{E}_2+{E}_3+{i}_3 {R}_1=0\)
4. \(-{i}_2 {R}_2+{E}_2+{E}_3+{i}_3{R}_1=0\)
Subtopic:  Kirchoff's Voltage Law |
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A battery of emf \(10\) V is connected to resistance as shown in the figure below. The potential difference \(V_{A} - V_{B}\)
between the points \(A\) and \(B\) is:

 

1. \(-2\) V

2. \(2\) V

3. \(5\) V

4. \(\frac{20}{11}~\text{V}\)

Subtopic:  Kirchoff's Voltage Law |
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Consider the circuit shown in the figure below. The current \(I_3\) is equal to:

       

1. \(5\) A

2. \(3\) A

3. \(-3\) A

4. \(\frac{-5}{6}\) A

Subtopic:  Kirchoff's Voltage Law |
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