- 1(current)
Q. No.The amplitude of the charge oscillating in a circuit decreases exponentially as \(\mathrm{Q=Q_{0}e}^{-Rt/2L}\) where \({Q}_0\) is the charge at \({t}=0~\text{s}.\)The time at which charge amplitude decreases to \(0.50~{Q}_0\) is nearly:
\((\text{Given that}~ {R=1.5~\Omega,~L=12~\text{mH},~\text{ln}(2)=0.693})\)
1. \(19.01~\text{ms}\)
2. \(11.09~\text{ms}\)
3. \(19.01~\text s\)
4. \(11.09~\text s\)
\((\text{Given that}~ {R=1.5~\Omega,~L=12~\text{mH},~\text{ln}(2)=0.693})\)
1. \(19.01~\text{ms}\)
2. \(11.09~\text{ms}\)
3. \(19.01~\text s\)
4. \(11.09~\text s\)
Subtopic: RC Circuit (OLD NCERT) |
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