- 1(current)
Q. No.
When the separation between two charges is increased, the electric potential energy of the charges:
1. increases
2. decreases
3. remains the same
4. may increase or decrease
As per this diagram, a point charge \(+q\) is placed at the origin \(O.\) Work done in taking another point charge \(-Q\) from the point \(A,\) coordinates \((0,a),\) to another point \(B,\) coordinates \((a,0),\) along the straight path \(AB\) is:
| 1. | \( \left(\dfrac{-{qQ}}{4 \pi \varepsilon_0} \dfrac{1}{{a}^2}\right) \sqrt{2} {a}\) | 2. | zero |
| 3. | \( \left(\dfrac{qQ}{4 \pi \varepsilon_0} \dfrac{1}{{a}^2}\right) \dfrac{1}{\sqrt{2}} \) | 4. | \( \left(\dfrac{{qQ}}{4 \pi \varepsilon_0} \dfrac{1}{{a}^2}\right) \sqrt{2} {a}\) |
The potential energy of the system of charges is \(U_0.\) If the charges are brought closer so that each side of the square is \(1~\text m,\) then the new potential energy of the system will be:
| 1. | \(U_0\) | 2. | \(\dfrac{U_0}{2}\) |
| 3. | \(2U_0\) | 4. | \(4U_0\) |
A positively charged light particle of charge \(q\) and mass \(m\) approaches another heavy particle of positive charge \(Q,\) coming towards it with an initial speed \(u,\) when it is far away.
The distance of the closest approach is given by:
1. \(\frac{q Q}{4 \pi \varepsilon_{0} m u^{2}}\)
2. \(\frac{q Q}{\pi \varepsilon_{0} m u^{2}}\)
3. \(\frac{q Q}{2 \pi \varepsilon_{0} m u^{2}}\)
4. \(\frac{4 \pi \varepsilon_{0} m u^{2}}{q Q}\)
- 1(current)
Q. No.
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