- 1(current)
Q. No.The viscous drag acting on a metal sphere of diameter \(1\) mm, falling through a fluid of viscosity \(0.8\) Pa-s with a velocity of \(2\) ms–1 is nearly equal to:
1. \(15\times 10^{-3}~\text{N}\)
2. \(30\times 10^{-3}~\text{N}\)
3. \(1.5\times 10^{-3}~\text{N}\)
4. \(20\times 10^{-3}~\text{N}\)
1. \(15\times 10^{-3}~\text{N}\)
2. \(30\times 10^{-3}~\text{N}\)
3. \(1.5\times 10^{-3}~\text{N}\)
4. \(20\times 10^{-3}~\text{N}\)
Subtopic: Stokes' Law |
Please attempt this question first.
Please attempt this question first.
Please attempt this question first.
Launched MCQ Practice Books
Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe terminal velocity of a copper ball of radius \(5~\text{mm}\) falling through a tank of oil at room temperature is \(10~\text{cm}~\text{s}^{-1}\) . If the viscosity of oil at room temperature is \(0.9~\text{kg}~\text{m}^{-1}~\text{s}^{-1}\), the viscous drag force is:
1. \(8.48 \times10^{-3}\) N
2. \(8.48 \times10^{-5}\) N
3. \(4.23 \times10^{-3}\) N
4. \(4.23 \times10^{-6}\) N
1. \(8.48 \times10^{-3}\) N
2. \(8.48 \times10^{-5}\) N
3. \(4.23 \times10^{-3}\) N
4. \(4.23 \times10^{-6}\) N
Subtopic: Stokes' Law |
To view explanation, please take trial in the course below.
NEET 2025 - Target Batch
To view explanation, please take trial in the course below.
NEET 2025 - Target Batch
Please attempt this question first.
Launched MCQ Practice Books
Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology- 1(current)
Q. No.
© 2024 GoodEd Technologies Pvt. Ltd.