For the diagram given below, a triangular lamina is shown. The correct relation between I₁, I₂ & I₃ is (I – moment of inertia)         
     

1. I₁ > I₂

2. I₂ > I₁

3. I₃ > I₁

4. I₃ > I₂

A circular disc is to be made by using iron and aluminium so that it acquires a maximum moment of inertia about its geometrical axis. It is possible with: 

The ratio of the radii of gyration of a circular disc about a tangential axis in the plane of the disc and of a circular ring of the same radius about a tangential axis in the plane of the ring will be:
1. \(2:1\)
2. $\sqrt{5}$ : $\sqrt{6}$
3. \(2:3\)
4. \(1:\) $\sqrt{2}$

Three particles, each of mass \(m\) gram, are situated at the vertices of an equilateral triangle ABC of side \(l\) cm (as shown in the figure). The moment of inertia of the system about a line AX, perpendicular to AB and in the plane of ABC, in gram-cm² units will be:

           
1. \(2ml^2\)
2. \(\frac{5}{4}ml^2\)
3. \(\frac{3}{2}ml^2\)
4. \(\frac{3}{4}ml^2\)

The moment of inertia of a uniform circular disc of radius 'R' and mass 'M' about an axis passing from the edge of the disc and normal to the disc is:

1. $\frac{1}{2}{\mathrm{MR}}^2$

2. $\frac{7}{2}{\mathrm{MR}}^2$

3. $\frac{3}{2}{\mathrm{MR}}^2$

4. ${\mathrm{MR}}^2$