- 1(current)
Q. No.The instantaneous angular position of a point on a rotating wheel is given by the equation,
\(\theta(t)=2t^{3}-6t^{2}\)
The torque on the wheel becomes zero at:
\(\theta(t)=2t^{3}-6t^{2}\)
The torque on the wheel becomes zero at:
| 1. | \(t=0.5\) s | 2. | \(t=0.25\) s |
| 3. | \(t=2\) s | 4. | \(t=1\) s |
Subtopic: Rotational Motion: Kinematics |
To view explanation, please take trial in the course below.
NEET 2025 - Target Batch
To view explanation, please take trial in the course below.
NEET 2025 - Target Batch
Please attempt this question first.
Launched MCQ Practice Books
Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyA wheel has an angular acceleration of \(3.0\) rad/s2 and an initial angular speed of \(2.0\) rad/s. In a time of \(2\) s, it has rotated through an angle (in radians) of:
| 1. | \(6\) | 2. | \(10\) |
| 3. | \(12\) | 4. | \(4\) |
Subtopic: Rotational Motion: Kinematics |
To view explanation, please take trial in the course below.
NEET 2025 - Target Batch
To view explanation, please take trial in the course below.
NEET 2025 - Target Batch
Please attempt this question first.
Launched MCQ Practice Books
Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot
NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology- 1(current)
Q. No.
© 2024 GoodEd Technologies Pvt. Ltd.