A block of mass \(m\) is placed on a smooth inclined wedge \(ABC\) of inclination \(\theta\) as shown in the figure. The wedge is given an acceleration '\(a\)' towards the right. The relation between \(a\) and \(\theta\) for the block to remain stationary on the wedge is:
          
1. \(a = \frac{g}{\text{cosec } \theta}\)
2. \(a = \frac{g}{\sin\theta}\)
3. \(a = g\cos\theta\)
4. \(a = g\tan\theta\)

Subtopic:  Application of Laws |
To view explanation, please take trial in the course below.
NEET 2025 - Target Batch
To view explanation, please take trial in the course below.
NEET 2025 - Target Batch
Please attempt this question first.
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology