A car is moving with velocity v. It stops after applying breaks at a distance of 20 m. If the velocity of the car is doubled, then how much distance it will cover (travel) after applying breaks?
1.  40 m
2.  80 m
3.  160 m
4.  320 m

Subtopic:  Uniformly Accelerated Motion |
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A body starts falling from height \(h\) and if it travels a distance of \(\frac{h}{2}\) during the last second of motion, then the time of flight is (in seconds):
1. \(\sqrt{2}-1\)
2. \(2+\sqrt{2}\)
3. \(\sqrt{2}+\sqrt{3}\)
4. \(\sqrt{3}+2\)

Subtopic:  Uniformly Accelerated Motion |
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A particle is thrown vertically upward. Its velocity at half its height is \(10\) m/s. Then the maximum height attained by it is: (Assume, \(g=\) \(10\) m/s2
1. \(8\) m
2. \(20\) m
3. \(10\) m
4. \(16\) m

Subtopic:  Uniformly Accelerated Motion |
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If a ball is thrown vertically upwards with speed \(u\), the distance covered during the last \(t\) seconds of its ascent is:
1. \(ut\)
2. \(\frac{1}{2}gt^2\)
3. \(ut-\frac{1}{2}gt^2\)
4. \((u+gt)t\)

Subtopic:  Uniformly Accelerated Motion |
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A man throws some balls with the same speed vertically upwards one after the other at an interval of \(2\) seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given \(g = 9.8\) m/s2)

1. More than \(19.6\) m/s
2. At least \(9.8\) m/s
3. Any speed less than \(19.6\) m/s
4. Only with a speed of \(19.6\) m/s
Subtopic:  Uniformly Accelerated Motion |
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A ball of mass 2 kg and another of mass 4 kg are dropped together from a 60 feet tall building. After a fall of 30 feet each towards the earth, their respective kinetic energies will be in the ratio of:

1. 1: 4

2. 1: 2

3. 1: 2

4. 2 :1

Subtopic:  Uniformly Accelerated Motion |
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