In [Cr(NH3)6](Br)3, number of unpaired electrons in Cr is:

1. 4 2. 3
3. 1 4. 2
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In a quantitative analysis of second group in the lab, H2S gas is passed in an acidic medium for ppt. When Cu+2 and Cd+2 react with KCN, then in which of the following conditions will a precipitate not be formed due to relative stability:
 

1. K2[Cu(CN)4] – More stable
K2[Cd(CN)4] – Less stable
2. K2[Cu(CN)4] – Less stable
K2[Cd(CN)4] – More stable
3. K3[Cu(CN)4] – More stable
K2[Cd(CN)4] – Less stable
4. K3[Cu(CN)4] – Less stable
K3[Cd(CN)4] – More stable
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The incorrect option among the following is:

1. Ni(CO)4, Tetrahedral, paramagnetic
2. [Ni(CN)4]2-, Square planar, diamagnetic
3. Ni(CO)4, Tetrahedral, diamagnetic
4. [Ni(Cl)4]2-, Tetrahedral, paramagnetic

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The atomic numbers of Cr and Fe are respectively 24 and 26. Among the following, the one that is paramagnetic with the spin of the electron is:

1. CrCO6

2. FeCO5

3. [Fe(CN)6]4-

4. [Cr(NH3)6]3+

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The number of unpaired electrons in the complex ion [CoF6]3– is:

(Atomic No. Co = 27)

1. 2

2. 3

3. 4

4. Zero

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In an octahedral structure, the pair of d orbitals involved in d2sp3 hybridization is:

1. dxz,dx2y2

2. dz2, dxz

3. dxy,dyz

4. dx2y2, dz2

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Considering H2O as a weak field ligand, the number of unpaired electrons in \([Mn(H_{2}O)_{6}]^{2+}\) will be:
(At. no. of Mn = 25)

1. Five 2. Two
3. Four 4. Three
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Among [Ni(CO)4], [Ni(CN)4]2−, [ NiCl4]2− species, the hybridization states of the Ni atom are respectively:
(At. No. of Ni = 28)

1. sp3, dsp2, sp3 2. sp3, sp3, dsp2
3. dsp2, sp3, sp3 4. sp3, dsp2 , dsp2
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Which one of the following is an inner orbital complex as well as is diamagnetic in behaviour?

1. [Zn (NH3)6]2+

2. [Ni (NH3)6]2+

3. [Cr (NH3)6]3+

4. [Co (NH3)6]3+

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