The standard cell potential of the following cell \(\mathrm{Zn}\left|\mathrm{Zn}^{2+}(\mathrm{aq}) \| \mathrm{Fe}^{2+}(\mathrm{aq})\right| \mathrm{Fe}~\text{ is }~0.32 \mathrm{~V}.\) Calculate the standard Gibbs energy change for the reaction:
\(\mathrm{Zn}(\mathrm{s})+\mathrm{Fe}^{2+}(\mathrm{aq}) \rightarrow \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Fe}(\mathrm{s})\)

(Given : \(1 \mathrm{~F}=96487 \mathrm{C} mol^{-1}\))

1. \(-61.75 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
2. \(+5.006 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
3. \(-5.006 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
4. \(+61.75 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Subtopic:  Relation between Emf, G, Kc & pH |
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R):
Assertion (A): In equation \(\Delta_{\mathrm{r}} \mathrm{G}=-\mathrm{nFE} _{\text {cell }}, \) value \(\mathrm{\Delta_rG }\) depends on n. 
Reason (R): \(\mathrm{E_{cell} }\) is an intensive property and \(\mathrm{\Delta_rG }\)  is an extensive property. 
In the light of the above statements choose the correct answer from the options given below: 
1. (A) is False but (R) is True. 
2. Both (A) and (R) are True and (R) is the correct explanation of (A)
3. Both (A) and (R) are True and (R) is not the correct explanation of (A)
4. (A) is True but (R) is False.
Subtopic:  Relation between Emf, G, Kc & pH |
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Standard electrode potential for the cell with cell reaction
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)
is 1.1 V. Calculate the standard Gibbs energy change for the cell reaction. (Given F = 96487 C mol–1)
1. –200.27 kJ mol–1 2. –212.27 kJ mol–1
3. –212.27 J mol–1 4. –200.27 J mol–1
Subtopic:  Relation between Emf, G, Kc & pH |
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For the cell reaction
 \(\mathrm{2Fe^{3+}(aq) \ + \ 2I^{-}(aq)\rightarrow 2Fe^{2+}(aq) \ + \ I_{2}(aq)}\)

\(E_{cell}^{o} \ = \ 0.24 \ V\) at 298 K. The standard Gibbs energy ∆rG of the cell reaction is:

[Given: 96500 C mol-1]

1. 23.16 kJ mol-1

2. -46.32 kJ mol-1

3. -23.16 kJ mol-1

4. 46.32 kJ mol-1

Subtopic:  Relation between Emf, G, Kc & pH |
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For a cell involving one electron Ecell=0.59 V at 298 K.
The equilibrium constant for the cell reaction is :
\(\mathrm{[Given~ that~ \frac {2.303 ~RT}{F} = 0.059 ~V~ at~ T = 298 K]}\)

1. 1.0×1030

2. 1.0×102

3. 1.0×105

4. 1.0×1010

Subtopic:  Relation between Emf, G, Kc & pH |
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