The value of E0 cell for the following reaction is:
\(Cu^{2+}+ Sn^{2+}\to Cu +Sn^{4+ } \)
(Given, equilibrium constant is 106)
1. | 0.17 | 2. | 0.01 |
3. | 0.05 | 4. | 1.77 |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyFor the disproportionation of copper:
2Cu+ → C u2+ + C u is:
(Given for Cu+2/Cu is 0.34 V & Eº for Cu+2/Cu+ is 0.15 V )
1. 0.49 V
2. – 0.19 V
3. 0.38 V
4. – 0.38 V
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyIn electrolysis of NaCl when Pt electrode is taken then H2 is liberated at the cathode while with Hg cathode it forms sodium amalgam because:
1. | Hg is more inert than Pt |
2. | More voltage is required to reduce H+ at Hg than at Pt |
3. | Na is dissolved in Hg while it does not dissolve in Pt |
4. | The concentration of H+ ions is larger when the Pt electrode is taken |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyConsider the following reaction:
\(\frac{4}{3} \mathrm{Al}(\mathrm{s})+\mathrm{O}_2(\mathrm{~g}) \rightarrow \frac{2}{3} \mathrm{Al}_2 \mathrm{O}_3(\mathrm{~s})\)
The minimum e.m.f. required to carry out the electrolysis of Al2O3 is:
(F = 96500 C mol–1)
1. 2.14 V
2. 4.28 V
3. 6.42 V
4. 8.56 V
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe EMF of a Daniel cell at 298 K is E1 Zn|ZnSO4(0.01 M) || CuSO4(1.0 M)|Cu.
When the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the EMF is changed to E2. The correct relationship between E1 and E2 is:
1. | E1 > E2 | 2. | E1 < E2 |
3. | E1 = E2 | 4. | E2 = 0 ≠ E1 |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology