The geometry of a complex species can be understood from the knowledge of the type of hybridization of orbitals of the central atom. The hybridization of orbitals of a central atom in and the geometry of the complex are respectively
1. | sp3, tetrahedral | 2. | sp3, square planar |
3. | sp3d2, octahedral | 4. | dsp2, square planar |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyWhich of the following oxides is acidic in nature?
1.
2.
3.
4.
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe exhibition of the highest coordination number depends on the availability of vacant orbitals in the central atom. Which of the following elements is not likely to act as a central atom in ?
1. B
2. Al
3. Ga
4. In
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyBoric acid is an acid because its molecule
1. Contains replaceable H+ ion
2. Gives up a proton
3. Accepts OH- from water releasing proton
4. Combines with proton from water molecule
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe correct order of Ionization enthalpy (∆iH kJ mol–1) for the elements of group 13 among the following is:
1. B > Al > Ga > In > Tl
2. B < Al < Ga < In < Tl
3. B < Al > Ga < In < Tl
4. B > Al < Ga > In < Tl
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyIn the structure of diborane,
1. | All hydrogen atoms lie in one plane and boron atoms lie in a plane perpendicular to this plane. |
2. | 2 boron atoms and 4 terminal hydrogen atoms lie in the same plane and 2 bridging hydrogen atoms lie in the perpendicular plane. |
3. | 4 bridging hydrogen atoms and boron atoms lie in one plane and two terminal hydrogen atoms lie in a plane perpendicular to this plane. |
4. | All the atoms are in the same plane. |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyA compound X, of boron, reacts with NH3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with lithium aluminum hydride. The compounds X and Y are represented by the formulas.
1. B2H6, B3N3H6
2. B2O3, B3N3H6
3. BF3, B3N3H6
4. B3N3H6, B2H6
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyWhich of the following statements are correct?
(Answer on the basis of the given figure.)
a. | The two bridged hydrogen atoms and the two boron atoms lie in one plane |
b. | Out of six B-H bonds, two bonds can be described in terms of 3-center-2-electron bonds |
c. | Out of six B-H bonds, four B-H bonds can be described in terms of 3 center 2 electron bonds |
d. | The four-terminal B-H bonds are two center-two electron angular bonds |
Choose the correct option
1. (a, b, c)
2. (b, c, d)
3. (a, c, d)
4. (a, b, d)
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology