EΘ values of some redox couples are given below. On the basis of these values choose the correct option.

EΘ values: Br2/Br-=+1.90
Ag+/Ag(s)=+0.80
Cu2+/Cu(s)=+0.34; 
I2(s)/I-=+0.54

1. Cu will reduce Br 2. Cu will reduce Ag
3. Cu will reduce I 4. Cu will reduce Br2
Subtopic:  Emf & Electrode Potential |
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Given below are two statements: 
Assertion (A): Among halogens, fluorine is the best oxidant.
Reason (R): Fluorine is the most electronegative atom.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Emf & Electrode Potential |
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Which of the following electrodes will act as anodes, when connected to Standard Hydrogen Electrode?
\(\begin{array}{rlr}\text { (a) } & \mathrm{{Al}^{3+} / {Al}} & \mathrm{{E}_{RP}^{o}=-1.66} \\\text { (b) } & \mathrm{{Fe}^{2+} / {Fe}} & \mathrm{{E}_{RP}^{o}=-0.44} \\\text { (c) } & \mathrm{{Cu}^{2+} / {Cu}} & \mathrm{{E}_{RP}^{o}=+0.34} \\\text { (d) } & \mathrm{{F}_{2}({~g}) / 2 {~F}^{-}({aq})} & \mathrm{{E}_{RP}^{o}=+2.87}\end{array}\)

   
The correct choice among the above is:

1. (a, b)

2. (b, c)

3. (c, d)

4. (a, d)

Subtopic:  Emf & Electrode Potential |
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