Standard reduction potentials of the half-reactions are given below:
The strongest oxidizing and reducing agents, respectively, are:
1. and
2. and
3. and
4. and
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe ion is unstable in solution and undergoes disproportionation reaction to give ion. The balanced ionic equation for the reaction is-
1. | \(\small{2 \mathrm{Mn}^{3+}{ }_{(\mathrm{aq})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} \rightarrow \mathrm{MnO}_{2(\mathrm{~s})}+\mathrm{Mn}^{2+}{ }_{(\mathrm{aq})}+4 \mathrm{H}^{+}{ }_{(\mathrm{aq})}}\) |
2. | Mn3+(aq) + H2O(l) → MnO2(s) + 2Mn2+(aq) + 4H+(aq) |
3. | \(\small{5 \mathrm{Mn}^{3+}(\mathrm{aq})+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} \rightarrow \mathrm{MnO}_{2(\mathrm{s})}+3 \mathrm{Mn}^{2+}(\mathrm{aq})+4 \mathrm{H}^{+}(\mathrm{aq})}\) |
4. | \(\small{2 \mathrm{Mn}^{3+}{ }_{(\mathrm{aq})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} \rightarrow 2 \mathrm{MnO}_{2(\mathrm{s})}+2 \mathrm{Mn}^{2+}{ }_{(\mathrm{aq})}+4 \mathrm{H}^{+}{ }_{(\mathrm{aq})}}\) |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe strongest oxidising agent among the following is :
1.
2.
3.
4.
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe correct statement about the given reaction is-
(CN)2(g) + 2OH-(aq) CN-(aq) + CNO-(aq) + H2O(l)
1. | The reaction is an example of a disproportionation reaction. |
2. | Hydrogen atom gets oxidized. |
3. | Reaction occurs in acidic medium. |
4. | None of the above |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe standard electrode potential (E°) values of Al3+/ Al, Ag+ / Ag, K+ / K, and Cr3+ / Cr are –1.66 V, 0.80 V, –2.93 V, & –0.79 V respectively. The correct decreasing order of the reducing power of the metal is:
1. | Ag > Cr > Al > K | 2. | K > Al > Cr > Ag |
3. | K > Al > Ag > Cr | 4. | Al > K > Ag > Cr |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology(a) | \(E_{k^+/K}^o = - 2.93\ V\); \(E_{Ag^+/Ag}^o = 0.80\ V\) |
(b) | \(E_{Hg^{2+}/Hg}^o = 0.79\ V\); \(E_{Mg^{2+}/Mg}^o = - 2.37\ V\) |
(c) | \(E_{Cr^{3+}/Cr}^o = -0.74\ V\) |
Based on standard electrode potentials given above, the correct arrangement for increasing order of reducing power of
elements is:
1. | \(\mathrm{Ag}<\mathrm{Hg}<\mathrm{Cr}<\mathrm{Mg}<\mathrm{K} \) |
2. | \(\mathrm{Ag}>\mathrm{Cr}>\mathrm{Mg}>\mathrm{Hg}>\mathrm{K}\) |
3. | \(\mathrm{K}>\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}>\mathrm{Ag} \) |
4. | \(\mathrm{K}<\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}<\mathrm{Ag}\) |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe correct statement about electrolysis of an aqueous solution of with Pt electrode is-
1. | Cu2+ ion reduced at the cathode; Cl- ion oxidized at the anode |
2. | Cu2+ ion reduced at the anode; Cl- ion oxidized at the cathode |
3. | Cu2+ ion reduced at the cathode; H2O ion oxidized at the anode |
4. | H2O ion reduced at the cathode; Cl- ion oxidized at the anode |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biologyvalues of some redox couples are given below. On the basis of these values choose the correct option.
1. | Cu will reduce Br– | 2. | Cu will reduce Ag |
3. | Cu will reduce I– | 4. | Cu will reduce Br2 |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyThe correct statement about the electrolysis of an aqueous solution of with Pt electrode is:
1. | Pt(s) gets oxidized at cathode whereas Ag + ( aq ) gets reduced at anode |
2. | Ag+ (aq) gets reduced at cathode and is oxidized at anode |
3. | Ag+ (aq) gets reduced at cathode whereas water is oxidized at anode |
4. | Ag (s) gets oxidized at cathode whereas H2O is oxidised at anode |
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & BiologyA solution contains Fe2+, Fe3+ and I– ions. This solution was treated with iodine at 35°C. E° for Fe3+/Fe2+ is +0.77 V and E° for I2/2I– = 0.536 V.
The favourable redox reaction is:
1. Fe2+ will be oxidized to Fe3+.
2. I2 will be reduced to I–.
3. There will be no redox reaction.
4. I– will be oxidized to I2.
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NEET MCQ Books for XIth & XIIth Physics, Chemistry & Biology