Consider the following reaction in a sealed vessel at equilibrium with concentrations of 
\(\text{N}_2=3.0 \times 10^{-3} \text{M}, \text{O}_2=4.2 \times 10^{-3} \text{M}\) and 
\(\text{NO}=2.8 \times 10^{-3}\)
\(2 \text{NO}_{(\text{g})} \rightleftharpoons \text{N}_{2(\text{g})} +\text{O}_{2\text{(g)}}\)
If 0.1 mol L-1 of NO(g) is taken in a closed vessel, what will be degree of dissociation (\(\alpha\)) of NO(g) at equilibrium?

1. 0.0889
2. 0.8889
3. 0.717
4. 0.00889
Subtopic:  Ionisation Constant of Acid, Base & Salt |
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For a weak acid HA, the percentage of dissociation is nearly 1% at equilibrium. If the concentration of acid is 0.1 mol L-1, then the correct option for its Ka at the same temperature will be:
1. \(1 \times 10^{-4}\)    
2. \(1 \times 10^{-6} \)
3. \(1 \times 10^{-5} \)
4. \(1 \times 10^{-3} \)
Subtopic:  Ionisation Constant of Acid, Base & Salt |
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