The standard enthalpy of neutralization is \(-57.3 \mathrm{~K}{\mathrm{J}}~ \mathrm{mol}^{-1}\)as:
\(\small{\underset{\text{strong acid}}{\mathrm{HCl_{(aq)}}}+\underset{\text{strong base}}{\mathrm{NaOH_{(aq)}}}\rightarrow\mathrm{NaCl_{(aq)}+H_2O(l),\Delta H=-57.3~KJ mol^{-1}}} \)
The enthalpy of neutralization of \(0.25 \mathrm{~mol}\) of HCI by \(0.25 \mathrm{~mol}\) of \(\mathrm{NaOH}\) is :

1. \(-57.3~ \mathrm{kJ} ~\mathrm{mol}^{-1}\)
2. \(-28.3 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
3. \(-14.32 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
4. \(+57.3~ \mathrm{kJ}~ \mathrm{mol}^{-1}\)
Subtopic:  Thermochemistry |
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Consider the following reaction:
\(\mathrm{2H_2(g) + O_2(g) \rightarrow 2H_2O(g) \Delta_rH^\circ = -483.64 kJ. }\)
What is the enthalpy change for the decomposition of one mole of water?
1. 120.9 kJ 2. 241.82 kJ
3. 18 kJ 4. 100 kJ
Subtopic:  Thermochemistry |
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At standard conditions, if the change in the enthalpy for the following reaction is –109 kJ mol
H2(g)+Br2(g)2HBr(g) and the bond energy of H2 and Br2 is 435 kJ mol–1 and 192 kJ mol–1 respectively, what is the bond energy (in kJ mol–1) of HBr?

1. 368 2. 736
3. 518 4. 259
Subtopic:  Thermochemistry |
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